问题描述
使用glutInitDisplayMode(GLUT_SINGLE|GLUT_RGB);之间有什么区别吗和glFlush()
Is there any difference between using, glutInitDisplayMode(GLUT_SINGLE|GLUT_RGB);withglFlush()
和glutInitDisplayMode(GLUT_DOUBLE|GLUT_RGB);与glutSwapBuffers()?
通过差异，我暗指代码的执行或显示吗?
By difference, I imply difference in the execution or display of code ?
推荐答案
在现代平台上存在巨大差异，从某种意义上来说，组合窗口管理器(例如Windows Vista +上的Aero)实际上拥有前缓冲区.如果绘制单个缓冲区，则永远不会发生缓冲区交换，最终结果是屏幕上将不会显示任何内容.
There is a huge difference on modern platforms, in the sense that compositing window mangers (e.g. Aero on Windows Vista+) effectively own the front-buffer. If you draw single buffered, a buffer swap never occurs, and the end result is that nothing will ever be displayed on the screen.
即使没有复合窗口管理器，这也会影响混合GPU的某些实现(例如，笔记本电脑上的Intel集成+ NVIDIA离散).在这样的系统上，缓冲区交换操作可以将离散GPU的帧缓冲区复制到集成的帧中，以进行最终输出.
This also affects some implementations of hybrid GPUs (e.g. Intel integrated + NVIDIA discrete on laptops) even without a compositing window manager. On such a system, the buffer swap operation is what copies the discrete GPU's framebuffer to the integrated for final output.
几乎没有理由在现代GPU上使用单缓冲渲染.过去，必须维护两个颜色缓冲区会占用大量内存，这也是反对三重缓冲的一个引人注目的论点，但如今，颜色缓冲区所需的内存量只是VRAM的一小部分.
There is almost no reason to use single-buffered rendering on modern GPUs. It used to be that having to maintain two color buffers ate a lot of memory, which was also a compelling argument against triple-buffering, but these days the amount of memory required for the color buffer is a minute fraction of VRAM.
这篇关于OpenGL缓冲区，gLFlush和glutSwapBuffers()的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！