本文介绍了使用带有opengl的C ++绘制椭圆?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧! 问题描述 29岁程序员,3月因学历无情被辞! Iam试图绘制一个不在我的项目中移动的椭圆,我在这个项目中使用动画,但使用函数'myellipse'使动画非常慢 这是绘制椭圆的代码 我尝试了什么: 这是绘制的代码椭圆 void myEllipse(int x,int y,float StAngle,float EndAngle,int RX,int RY) { double i; glBegin(GL_LINE_STRIP); glColor3f(1,1,0); i = StAngle; while(i< = EndAngle) { glVertex2f(int((RX * cos(i)+ y)+。5),int((RY * sin(i)+ x 。)+ 5)); i = i + .001; } glEnd(); } 这是我的动画代码 void 动画( void ) { if (angle> = 0 && angle< 10) angle = angle + 0。 5 ; else angle = 0 ; glutPostRedisplay(); } void 自动( void ) // 控制鱼的运动 { if (Autorun< = 300 &&& Autorun> - 350 ) Autorun = Autorun- 0 。 05 ; else Autorun = 300 ; glutPostRedisplay(); } 解决方案 你想提高速度,这个过程被命名为'优化',帮助你发现瓶颈的工具是探测器。 分析(计算机编程) - 维基百科 [ ^ ] 优化是关于你的代码的关键,它在回答问题时翻译: 为什么我这样做,是否有必要? 我可以得到更多相同的结果高效代码? 您的代码使用固定增量 i = i + .001 这意味着对于任何elipse,您循环6200次,无论如何elipse的大小。 评论家:如果我的话elipse是10像素,我需要循环6200次吗? 答案是否定的,我可以减少循环次数。 诀窍是调整增量到elipse的大小。 这样的东西可以提高速度: void myEllipse( int x, int y, float StAngle, float EndAngle, int RX, int RY) { double i ,inc ; glBegin(GL_LINE_STRIP); glColor3f( 1 , 1 , 0 ); inc = 3 .14 / max(RX,RY)/ 2; i = StAngle; while (i< = EndAngle) { glVertex2f( int ((R​​X * cos(i)+ y)+。 5 ), int ((RY * sin(i)+ x)+。 5 )); i = i + inc ; } glEnd(); } 如果你想要更快的elipses和圈子,你必须学习这篇文章: 圈子和数字差分分析仪| Dobb博士 [ ^ ] Iam trying to draw an ellipse that don't move in my project and i use animation in this project but using function 'myellipse' makes the animation very slowthis is the code to draw ellipseWhat I have tried:This is the code to draw an ellipsevoid myEllipse(int x,int y,float StAngle,float EndAngle,int RX, int RY){double i;glBegin(GL_LINE_STRIP);glColor3f(1,1,0);i=StAngle;while(i<=EndAngle){glVertex2f(int((RX*cos(i)+y)+.5),int((RY*sin(i)+x)+.5));i=i+.001;}glEnd();}and this is my code to animationvoid animation(void){if(angle>=0 && angle<10)angle = angle+0.5;else angle = 0;glutPostRedisplay();}void Auto(void) //Control the movment of the fish{if(Autorun<=300 && Autorun>-350)Autorun = Autorun-0.05;else Autorun = 300;glutPostRedisplay();} 解决方案You want to improve speed, that process is named 'optimization', the tool that help you to spot bottle necks is the profiler.Profiling (computer programming) - Wikipedia[^]Optimization is about being critical about your code, it translate at answering the questions:Why do I it that way, is it necessary ?Can I get same result with more efficient code ?Your code is using a fixed increment i=i+.001 which imply that for any elipse, you loop 6200 times, no matter the size of the elipse.Critics: if my elipse is 10 pixels across, do I need to loop 6200 times ?Answer is no, I can reduce the number of loops.The trick is to adapt the increment to the size of elipse.Something like this sould improve speed:void myEllipse(int x,int y,float StAngle,float EndAngle,int RX, int RY){double i, inc;glBegin(GL_LINE_STRIP);glColor3f(1,1,0);inc=3.14/max(RX,RY)/2;i=StAngle;while(i<=EndAngle){glVertex2f(int((RX*cos(i)+y)+.5),int((RY*sin(i)+x)+.5));i=i+inc;}glEnd();}If you want real faster elipses and circles, you have to study this article:Circles and the Digital Differential Analyzer | Dr Dobb's[^] 这篇关于使用带有opengl的C ++绘制椭圆?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持! 上岸,阿里云!
08-05 02:32