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问题描述

我想解析一个包含以下结构的文件:

I want to parse a file containing the following structure:

some
garbage *&%
section1 {
    section_content
}
section2 {
    section_content
}

解析section_name1 { ... } section_name2 { ... } 的规则已经定义:

The rule parsing section_name1 { ... } section_name2 { ... } is already defined:

section_name_rule = lexeme[+char_("A-Za-z0-9_")];
section = section_name_rule > lit("{") > /*some complicated things*/... > lit("}");
sections %= +section;

所以我需要跳过任何垃圾,直到满足 sections 规则.有什么办法可以做到这一点吗?我试过 seek[sections],但它似乎不起作用.

So I need to skip any garbage until the sections rule is met.Is there any way to accomplish this? I have tried seek[sections], but it seems not to work.

编辑:我本地化了seek不起作用的原因:如果我使用跟随操作符(>>),那么它就起作用了.如果使用了期望解析器 (>),则会抛出异常.这是一个示例代码:

EDIT:I localized the reason why seek is not working: if I use follows operator(>>), then it works. If expectation parser is used (>), then it throws an exception. Here is a sample code:

#define BOOST_SPIRIT_DEBUG
#include <boost/fusion/adapted/struct.hpp>
#include <boost/spirit/include/qi.hpp>
#include <boost/spirit/repository/include/qi_seek.hpp>
#include <boost/spirit/include/phoenix.hpp>

namespace qi = boost::spirit::qi;
using boost::phoenix::push_back;

struct section_t {
    std::string name, contents;
    friend std::ostream& operator<<(std::ostream& os, section_t const& s) { return os << "section_t[" << s.name << "] {" << s.contents << "}"; }
};

BOOST_FUSION_ADAPT_STRUCT(section_t, (std::string, name)(std::string, contents))

    typedef std::vector<section_t> sections_t;

    template <typename It, typename Skipper = qi::space_type>
    struct grammar : qi::grammar<It, sections_t(), Skipper>
{
    grammar() : grammar::base_type(start) {
        using namespace qi;
        using boost::spirit::repository::qi::seek;
        section_name_rule = lexeme[+char_("A-Za-z0-9_")];
        //Replacing '>>'s with '>'s throws an exception, while this works as expected!!
        section = section_name_rule
            >>
            lit("{") >> lexeme[*~char_('}')] >> lit("}");
        start = seek [ hold[section[push_back(qi::_val, qi::_1)]] ]
            >> *(section[push_back(qi::_val, qi::_1)]);
    }
    private:
    qi::rule<It, sections_t(),  Skipper> start;
    qi::rule<It, section_t(),   Skipper> section;
    qi::rule<It, std::string(), Skipper> section_name_rule;
};

int main() {
    typedef std::string::const_iterator iter;
    std::string storage("sdfsdf
 sd:fgdfg section1 {dummy } section2 {dummy  } section3 {dummy  }");
    iter f(storage.begin()), l(storage.end());
    sections_t sections;
    if (qi::phrase_parse(f, l, grammar<iter>(), qi::space, sections))
    {
        for(auto& s : sections)
            std::cout << "Parsed: " << s << "
";
    }
    if (f != l)
        std::cout << "Remaining unparsed: '" << std::string(f,l) << "'
";
}

所以在真实的例子中,我的整个语法都是用期望运算符构建的.我是否必须更改所有内容才能使寻求"工作,还是有其他方法(比方说,寻求一个简单的{",然后恢复一个 section_name_rule)??

So in the real example my entire grammar is constructed with expectation operators. Do I have to change everything to make the "seek" work, or is there any other way (let's say, seek a simple "{", and revert one section_name_rule back)??

推荐答案

这里有一个演示,以哈姆雷特为灵感:生活在 Coliru

Here's a demonstration, using Hamlet for inspiration: Live On Coliru

start = *seek [ no_skip[eol] >> hold [section] ];

注意事项:

  • 降低期望值
  • 通过要求在部分名称之前开始行来进行优化

示例输入:

some
garbage *&%
section1 {
   Claudius: ...But now, my cousin Hamlet, and my son —
   Hamlet: A little more than kin, and less than kind.
}
WE CAN DO MOAR GARBAGE
section2 {
   Claudius: How is it that the clouds still hang on you?
   Hamlet: Not so my lord; I am too much i' the sun
}

输出:

Parsed: section_t[section1] {Claudius: ...But now, my cousin Hamlet, and my son —
   Hamlet: A little more than kin, and less than kind.
}
Parsed: section_t[section2] {Claudius: How is it that the clouds still hang on you?
   Hamlet: Not so my lord; I am too much i' the sun
}

参考清单

// #define BOOST_SPIRIT_DEBUG
#include <boost/fusion/adapted/struct.hpp>
#include <boost/spirit/include/qi.hpp>
#include <boost/spirit/repository/include/qi_seek.hpp>

namespace qi = boost::spirit::qi;

struct section_t {
    std::string name, contents;
    friend std::ostream& operator<<(std::ostream& os, section_t const& s) { return os << "section_t[" << s.name << "] {" << s.contents << "}"; }
};

BOOST_FUSION_ADAPT_STRUCT(section_t, (std::string, name)(std::string, contents))

typedef std::vector<section_t> sections_t;

template <typename It, typename Skipper = qi::space_type>
struct grammar : qi::grammar<It, sections_t(), Skipper>
{
    grammar() : grammar::base_type(start) {
        using namespace qi;
        using boost::spirit::repository::qi::seek;

        section_name_rule = lexeme[+char_("A-Za-z0-9_")];
        section           = section_name_rule >> '{' >> lexeme[*~char_('}')] >> '}';
        start             = *seek [ no_skip[eol] >> hold [section] ];

        BOOST_SPIRIT_DEBUG_NODES((start)(section)(section_name_rule))
    }
  private:
    qi::rule<It, sections_t(),  Skipper> start;
    qi::rule<It, section_t(),   Skipper> section;
    qi::rule<It, std::string(), Skipper> section_name_rule;
};

int main() {
    using It = boost::spirit::istream_iterator;
    It f(std::cin >> std::noskipws), l;

    sections_t sections;
    if (qi::phrase_parse(f, l, grammar<It>(), qi::space, sections))
    {
        for(auto& s : sections)
            std::cout << "Parsed: " << s << "
";
    }
    if (f != l)
        std::cout << "Remaining unparsed: '" << std::string(f,l) << "'
";
}

这篇关于Boost Spirit还原解析的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

08-05 00:42