问题描述
我有一个Boost多索引结构，该结构将boost :: shared_ptr保留到A类的实例.当我使用索引之一的查找"功能时，我得到一个迭代器"it"，从中可以通过A* a = it->get();返回实际指针.知道多索引结构的erase函数需要一个迭代器，而不是指针或boost :: shared_ptr，我如何才能从多索引中删除a呢?问题是在程序中要删除对象的地方，我不再有我的初始迭代器，只有实际的指针.
I have a boost multi-index structure that keeps boost::shared_ptr to instances of a class A.When I use the "find" function of one of the index, I get an iterator "it" from which I can get back the actual pointer through A* a = it->get();. How can I delete a from the multi-index knowing that the erase function of the multi-index structure takes an iterator, not a pointer nor a boost::shared_ptr? The thing is at the point of the program where I want to erase the object, I don't have anymore my initial iterator, only the actual pointer.
谢谢
推荐答案
没有这样的东西多索引结构的erase功能".请注意，erase是 index 的成员函数，其签名可能会因索引类型而异.
There is no such thing "erase function of the multi-index structure". Note that erase is a member-function of an index, and its signature may vary depending on the index type.
尤其是，有序索引和哈希索引具有在erase的超载之后:
In particular, ordered and hashed indices have the following overloads of erase:
iterator erase(iterator position);
size_type erase(const key_type& x);
iterator erase(iterator first,iterator last);
即如果shared_ptr是键，则可以将其传递给erase函数.当然，您可以先调用find，获取迭代器并将其传递给erase.
I.e. if shared_ptr is a key, you definitely can pass it to erase function.Of course, you can call find first, get the iterator and pass it to erase.
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