本文介绍了如何将以下C ++代码转换为XML的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
#include<iostream>
#include<string>
#include<stdlib.h>
#include<process.h>
#include<windows.h>
using namespace std;
class current
{
private:
char choice;
int x,y;
public:
current()
{
}
void currentcash()
{
char ch;
cout<<"\n\n\n\n\n\n\n\n\n\nWell come to UBL\n\n";
Sleep(3000);
system("cls");
cout<<"\n\n\n\n\n\n\n\n\n\nPlease enter you card and Press any key\n\n";
cin>>choice;
cout<<"\n\n\n\n\n\n\n\n\n\nHave you entered the card?\nPress 1 for 'YES' and 0 for 'NO'\n\n";
cin>>x;
if(x==0)
{
return;
}
cout<<"\n\n\n\n\n\n\n\n\n\nPlease enter your four digit pin code\n\n";
cin>>y;
for(y=1;y<=4;y++)
{
if(y>='0' && y<='9')
{
cout<<"*";
}
}
}
};
int total=100000;
class fastcash
{
public:
public:
fastcash()
{
total=100000;
}
void operatecash()
{
int a;
//int total;
if(total==0)
{
cout<<"You have not sufficient balance";
Sleep(6000);
return;
}
cout<<"\n\nPress 1 for 'RS.500' \n";
cout<<"Press 2 for 'RS.1000' \n";
cout<<"Press 3 for 'RS.1500' \n";
cout<<"Press 4 for 'RS.2000' \n";
cout<<"Press 5 for 'RS.2500' \n";
cout<<"Press 6 for 'RS.25000' \n";
cout<<"Press 0 for Main Menu \n";
cin>>a;
if(a==1 || a==2 || a==3 || a==4 || a==5 ||a==6)
{
int b;
if(a==1)
total-=500;
if(a==2)
total-=1000;
if(a==3)
total-=1500;
if(a==4)
total-=2000;
if(a==5)
total-=2500;
if(a=6)
total-=25000;
cout<<"\nDo you want to make another transection press 1?";
cin>>b;
if (b==1)
{
operatecash();
}
else
{
cout<<"No\n";
cout<<"\n\n\n\nThanks for banking with UBL";
Sleep(2000);
{
system("cls");
Sleep(8000);
return;
//current::currentcash();
}
}
}
}
};
class cashinquiry:public current
{
public:
void operateinquiry()
{
int b;
cout<<total;
cout<<"\n\nDo you want to have receipt?\nPress 1 for 'Yes' else anyother key";
cin>>b;
if(b==1)
{
cout<<"Yes\n";
Sleep(2000);
cout<<"\n\n\n\nThanks for banking with UBL";
Sleep(2000);
{
system("cls");
Sleep(8000);
current::currentcash();
}
}
else
{
cout<<"No\n";
cout<<"\n\n\n\nThanks for banking with UBL";
Sleep(2000);
{
system("cls");
Sleep(8000);
current::currentcash();
}
}
}
};
class fundtransfer:public current
{
public:
void operatefund()
{
int c,d,e,f;
cout<<"How much money do you want to transfer?\n";
cin>>c;
if(total<c)>
{
cout<<"You don't have that much money to transfer\n";
Sleep(6000);
return;
}
total=total-c;
cout<<"Enter the account number in which you want to transfer money\n";
cin>>d;
cout<<"\n\nAre you sure that you want to transfer money?\n Press 1 for 'Yes' else anyother key\n\n";
cin>>e;
if(e==1)
{
cout<<"Yes\n";
}
else
{
cout<<"No\n";
}
cout<<"Do you want to make another money transfer?\nPress 1 for 'YES' and 0 for 'NO'\n";
cin>>f;
if(f==0)
{
system("cls");
cout<<"\n\n\n\nThanks for banking with UBL";
Sleep(2000);
{
system("cls");
Sleep(8000);
current::currentcash();
}
}
}
};
int main()
{
system ("color 1f");
current c;
fastcash fc;
cashinquiry ci;
fundtransfer ft;
c.currentcash();
int i;
while(1)
{
system("cls");
cout<<"\n\nPlease select Transection type\n\n";
cout<<"\n\nPress 1 for 'FAST CASH' \n";
cout<<"Press 2 for 'ACCOUNT INQUIRY' \n";
cout<<"Press 3 for 'FUND TRANSFER' \n";
cout<<"Press 0 for 'Exit' \n";
cin>>i;
switch(i)
{
case 1:
fc.operatecash();
break;
case 2:
ci.operateinquiry();
break;
case 3:
ft.operatefund();
break;
case 0:
exit(0);
}
}
system("pause");
}
[edit]已添加代码块 - OriginalGriff [/ edit]
[edit]Code block added - OriginalGriff[/edit]
推荐答案
<atminputs>
<transaction type="" /> <!-- 1= FASTCASH, 2 = BALANCEINQUIRY, 3 = FUNDTRANSFER -->
<fastcash amount="" /> <!-- user needs to fill this -->
<balanceinquiry receipt="" pincode="" />
<fundtransdfer amount="" toaccount="" />
<atminputs>
因此这将成为您的用户输入XML,然后休息处理保持不变。
所以只需解析xml的输入然后执行其余操作。
如果用户将值设置为1,则表示标签fastcash中的readonly值并进行处理。
so this becomes your input XML from user, and then rest processing remains the same.
so just parse the inputs from the xml and then do rest of the operations.
Like if user sets value as 1, then readonly values present in tag fastcash and do the processing.
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