getrefcount的意外结果

getrefcount的意外结果

本文介绍了来自sys.getrefcount的意外结果的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

当我输入时:

  

它不是 astrd 但值 123 。 astrd 仅仅是(不可变的)数字123的名称,可以多次引用。除此之外,小整数通常是共享的:

 >>> astrd = 123 
>>> sys.getrefcount(astrd)
4
>>> j = 123
>>> sys.getrefcount(astrd)
5

在第二个任务中,没有创建新的整数,而不是 j 只是整数 123 的新名称。



然而,给定非常大的整数,这并不成立:

 >>> i = 823423442583 
>>> sys.getrefcount(i)
2
>>> j = 823423442583
>>> sys.getrefcount(i)
2

共享整数是CPython的实现细节其他)。由于小整数经常被实例化,共享它们会节省大量的内存。这是因为整数是不可变的这一事实。



有关第二个示例中的附加参考,请参阅参考资料。 。


When I typed:

>>> astrd = 123
>>> import sys
>>> sys.getrefcount(astrd)
3
>>>

I am not getting where is astrd used 3 times ?

解决方案

It's not astrd that is referenced three times, but the value 123. astrd is simply a name for the (immutable) number 123, which can be referenced however many times. Additionally to that, small integers are usually shared:

>>> astrd = 123
>>> sys.getrefcount(astrd)
4
>>> j = 123
>>> sys.getrefcount(astrd)
5

In the second assignment, no new integer is created, instead j is just a new name for the integer 123.

However, given very large integers, this does not hold:

>>> i = 823423442583
>>> sys.getrefcount(i)
2
>>> j = 823423442583
>>> sys.getrefcount(i)
2

Shared integers are an implementation detail of CPython (among others). Since small integers are instantiated very often, sharing them saves a lot of memory. This is made possible by the fact that integers are immutable in the first place.

For the additional reference in the second example, cf. codeape's answer.

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08-04 19:48