如何知道一个角色是否是一个元音。

问题描述

#include<iostream>
#include<string>
#include<fstream>

using namespace std;

int main(){
string sSentence;
ifstream myfile ("example.txt");
  if (myfile.is_open())
  {
    while ( getline (myfile,sSentence) )
    {
      cout << sSentence << '\n';
    }
    myfile.close();
  }
	else cout << "Unable to open file";

int iLen = sSentence.length();
int iBlank = sSentence.find(" ");

char cVowels[]={"AEIOUaeiou"};

	for(int o=0;0<iLen;o++){
			if(isalpha(sSentence[o]) && sSentence[o] == cVowels ){
					string sSen = sSentence.substr(o,iBlank);
					int iLength = sSen.length();
					int iVowel = sSen.find_first_of("aeiouAEIOU");
					string addSent = sSen.substr(0,iVowel);
					string newSent = sSen.insert(iLength,addSent);
					cout << newSent;
					cout<<"ay";
					o=iBlank-1;
				}

			else
		        cout << sSentence[o];
	}
return 0;
}

i有此条件

i have this condition

char cVowels[]={"AEIOUaeiou"};
if(isalpha(sSentence[o]) && sSentence[0] == cVowels )

条件表明该字符是一个字母，它必须是一个元音。

如何将字符与cVowels进行比较???



当我运行代码时说：

[错误]预期主要 - 在']'之前的表达式令牌

the condition states that the character is a letter and it must be a vowel.
how can I compare the character to cVowels???

when I run the code it says:
"[error] expected primary - expression before ']' token

推荐答案

switch (sSentence[index])
{
	case 'a':
	case 'A':
	case 'e':
	case 'E':
	case 'i':
	case 'I':
	case 'o':
	case 'O':
	case 'u':
	case 'U':
                // character is a vowel
                // do something here
                break;

    default:
                // not a vowel
                // do something else here
}

编辑：添加方法显示使用一个函数。

Added approach showing the use of a function.

#include <cstdlib>
#include <cstdio>
#include <cstring>

bool isCharOneOf(char lookForMe, const char *inHere)
{
    while (*inHere)
    {
        if (lookForMe == *inHere)
            return true;
        inHere++;
    }
    return false;
}

int main(int argc, char *argv[])
{
    const char *searchString = "The quick brown fox jumps over the lazy dog";
    const char *vowels = "aeiouAEIOU";

    int nChars, curIndex, nVowels=0;
    nChars = strlen(searchString);
    for (curIndex=0; curIndex<nChars; curIndex++)
    {
        if (isCharOneOf(searchString[curIndex], vowels) == true)
            nVowels++;
    }
    printf("There are %d vowels in '%s'\n", nVowels, searchString);

    return 0;
}

引用：

if（isalpha（sSentence [o]）&& sSentence [o] == cVowels）

if(isalpha(sSentence[o]) && sSentence[o] == cVowels )

to

to

int n;
for (n=0; n<sizeof(cvowels); n++)  {
  if ( sSentence[o] == cVowels[n])
  { // OK, it is a vowel, do stuff here
   //..
   break;
  }
}
if ( n == sizeof(cvowels))
{ // no match: it is not a vowel
}

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