使用字符串标记设置创建数组了一个文本文件？

问题描述

哎。你可能最近看到一个帖子被我寻求帮助，但我做到了以前错误的，所以我要重新开始，并在从基础教起。

Hey. You may have recently seen a post by me looking for help, but I did it wrong before, so I am going to start fresh and begin at the basics.

我想读的文本文件看起来像这样：

I am trying to read a text file that looks like this:

FTFFFTTFFTFT结果
  3054 FTFFFTTFFTFT结果
  4674 FTFTFFTTTFTF结果
  ...等

我需要做的就是把第一行成一个String作为答案的关键是什么。

What I need to do is put the first line into a String as the answer key.

接下来，我需要建立与学生证（第一号）的数组。
然后，我需要创建一个数组，它是平行于包含学生回答学生的ID。

Next, I need to create an array with the student ID (the first numbers).Then, I need to create an array that is parallel to the student ID that contains the student's answers.

下面是我的code，我不能完全弄清楚如何得到它像这样的工作，我想知道，如果有人可以帮助我了。

Below is my code, and I can't quite figure out how to get it to work like this, and I was wondering if someone could help me out with it.

public static String[] getData() throws IOException {
      int[] studentID = new int[50];
      String[] studentAnswers = new String[50];
      int total = 0;

      String line = reader.readLine();
      strTkn = new StringTokenizer(line);
      String answerKey = strTkn.nextToken();

      while(line != null) {
        studentID[total] = Integer.parseInt(strTkn.nextToken());
        studentAnswers[total] = strTkn.nextToken();
        total++;
      }
    return studentAnswers;
    }

因此​​，在一天结束时，该阵列结构应该是这样的：

So at the end of the day, the array structure should look like:

studentID [0] = 3054搜索
studentID [1] = 4674搜索
...等

studentID[0] = 3054
studentID[1] = 4674
... etc

studentAnswers [0] = FTFFFTTFFTFT结果
studentAnswers [1] = FTFTFFTTTFTF

studentAnswers[0] = FTFFFTTFFTFT
studentAnswers[1] = FTFTFFTTTFTF

感谢：）

推荐答案

假设你已经阅读（因为我看不到读者变量的初始化或阅读器的类型）正确打开的文件和内容（根据你所期望的）文件是良好的，你必须做到以下几点：

Assuming you have opened the file correctly for reading (because I can't see how the reader variable is initialized or the type of the reader) and the contents of the file are well-formed (according to what you expect), you have to do the following:

  String line = reader.readLine();
  String answerKey = line;
  StringTokenizer tokens;
  while((line = reader.readLine()) != null) {
    tokens = new StringTokenizer(line);
    studentID[total] = Integer.parseInt(tokens.nextToken());
    studentAnswers[total] = tokens.nextToken();
    total++;
  }

当然，如果你为了避免运行时错误的情况下（文件的内容是不正确的）添加一些检查，这将是最好的，例如周围的Integer.parseInt的try-catch子句（）（可能会抛出NumberFormatException异常）。

Of course it would be best if you add some checks in order to avoid runtime errors (in case the contents of the file are not correct), e.g. try-catch clause around Integer.parseInt() (might throw NumberFormatException).

编辑：我刚才注意到您要使用的StringTokenizer你的标题，所以我编辑我的code（更换分裂法与StringTokenizer的）

I just notice in your title that you want to use StringTokenizer, so I edited my code (replaced the split method with the StringTokenizer).

这篇关于使用字符串标记设置创建数组了一个文本文件？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！