ASP.NET的WebForms：Request.GetFriendlyUrlFileVirtualPath（）返回空字符串

问题描述

我有只有几页简单的ASP.NET WebForms的项目，我想使用友好的URL（不仅是搜索引擎优化，也网址本地化）。我使用.NET 4.5的这个项目，并试图利用Microsoft.AspNet.FriendlyUrls的NuGet包，它看起来像它可能会帮助。但有一个问题。

I have got simple ASP.NET WebForms project with only few pages and I would like to use friendly URLs (not only for SEO but also localization of URLs). I use .NET 4.5 for this project and have tried to use Microsoft.AspNet.FriendlyUrls nuget package which looked like it might help. But there is one issue.

我有在Global.asax中这样的：

I've got in Global.asax this:

    void Application_Start(object sender, EventArgs e)
    {
        // Code that runs on application startup
        BundleConfig.RegisterBundles(BundleTable.Bundles);
        RouteConfig.RegisterRoutes(RouteTable.Routes);
    }

和RouteConfig类看起来是这样的：

and RouteConfig class looks like this:

public static class RouteConfig
{
    public static void RegisterRoutes(RouteCollection routes)
    {
        routes.MapPageRoute("HowItWorks", "ako-to-funguje", "~/HowItWorks.aspx");
        routes.MapPageRoute("AboutUs", "o-nas", "~/AboutUs.aspx");
        routes.MapPageRoute("Contact", "kontakt", "~/Contact.aspx");

        var settings = new FriendlyUrlSettings();
        settings.AutoRedirectMode = RedirectMode.Permanent;
        routes.EnableFriendlyUrls(settings);
    }
}

我想，如果你通过两个访问它显示在同一页/ HowItWorks和/ AKO到funguje（这是斯洛伐克环境）。

I want to show the same page if you access it through both /HowItWorks and /ako-to-funguje (which is Slovak locale).

，现在我越来越接近实际问题。当我访问的网站提供本地化的路线（如/ AKO到funguje），然后Request.GetFriendlyUrlFileVirtualPath（）返回空字符串之一（但我想获得〜/ HowItWorks.aspx赖以我想要做的主人一些东西页）。

And now I am getting close to actual issue. When I access site with one of localized routes (e.g. /ako-to-funguje) then Request.GetFriendlyUrlFileVirtualPath() returns empty string (but I want to get "~/HowItWorks.aspx" upon which I want to do some stuff in master page).

 string pageFileName = Request.GetFriendlyUrlFileVirtualPath();
 switch (pageFileName)
 {
      case "~/AboutUs.aspx":
           //do some stuff
           break;
      case "~/HowItWorks.aspx":
           //do some stuff
           break;
      case "~/Contact.aspx":
           //do some stuff
           break;
      default:
           break;
 }

如果我访问站点/ HowItWorks URL然后Request.GetFriendlyUrlFileVirtualPath（）返回〜/ HowItWorks.aspx作为预期。

If I access site with /HowItWorks URL then Request.GetFriendlyUrlFileVirtualPath() returns "~/HowItWorks.aspx" as expected.

不知道如何得到〜/ HowItWorks.aspx从Request.GetFriendlyUrlFileVirtualPath（）通过两个/ HowItWorks和/ AKO到funguje访问网站的时候？

Any idea how to get "~/HowItWorks.aspx" from Request.GetFriendlyUrlFileVirtualPath() when accessing site through both /HowItWorks and /ako-to-funguje?

推荐答案

最后我想出了这个问题的解决方法本身。我已经为HTTP请求自己的扩展方法，当前执行的页面，返回虚拟文件路径：

At the end I've come up with own workaround of this issue. I've created own extension method for http request which returns virtual file path to currently executed page:

 using System.Web;
 using System.Web.Routing;
 using Microsoft.AspNet.FriendlyUrls;

 namespace Utils.Extensions
 {
      public static class HttpRequestExtensions
      {
          public static string GetFileVirtualPathFromFriendlyUrl(this HttpRequest request) 
          {
             string ret = string.Empty;

             ret = request.GetFriendlyUrlFileVirtualPath();

             if (ret == string.Empty)
             {
               foreach (RouteBase r in RouteTable.Routes)
               {
                   if (r.GetType() == typeof(Route))
                   {
                       Route route = (Route)r;
                       if ("/" + route.Url == request.Path)
                       {
                           if (route.RouteHandler.GetType() == typeof(PageRouteHandler))
                           {
                               PageRouteHandler handler = (PageRouteHandler)route.RouteHandler;

                               ret = handler.VirtualPath;
                           }
                           break;
                       }
                   }
               }
             }

             return ret;
          }
     }
 }

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