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问题描述
有没有什么好方法可以使用PHPUnit在抽象类中模拟具体方法?
Are there any good ways to mock concrete methods in abstract classes using PHPUnit?
到目前为止,我发现的是:
- expects()-> will()使用抽象方法可以很好地工作
- 它不适用于具体方法.而是运行原始方法.
- 使用模拟生成器,并将所有抽象方法和具体方法提供给setMethods()工作.但是,它要求您指定所有抽象方法,从而使测试易碎且过于冗长.
- MockBuilder :: getMockForAbstractClass()忽略setMethod().
以下是一些可以证明以上几点的单元测试:
Here are some unit tests examplifying the above points:
abstract class AbstractClass {
public function concreteMethod() {
return $this->abstractMethod();
}
public abstract function abstractMethod();
}
class AbstractClassTest extends PHPUnit_Framework_TestCase {
/**
* This works for abstract methods.
*/
public function testAbstractMethod() {
$stub = $this->getMockForAbstractClass('AbstractClass');
$stub->expects($this->any())
->method('abstractMethod')
->will($this->returnValue(2));
$this->assertSame(2, $stub->concreteMethod()); // Succeeds
}
/**
* Ideally, I would like this to work for concrete methods too.
*/
public function testConcreteMethod() {
$stub = $this->getMockForAbstractClass('AbstractClass');
$stub->expects($this->any())
->method('concreteMethod')
->will($this->returnValue(2));
$this->assertSame(2, $stub->concreteMethod()); // Fails, concreteMethod returns NULL
}
/**
* One way to mock the concrete method, is to use the mock builder,
* and set the methods to mock.
*
* The downside of doing it this way, is that all abstract methods
* must be specified in the setMethods() call. If you add a new abstract
* method, all your existing unit tests will fail.
*/
public function testConcreteMethod__mockBuilder_getMock() {
$stub = $this->getMockBuilder('AbstractClass')
->setMethods(array('concreteMethod', 'abstractMethod'))
->getMock();
$stub->expects($this->any())
->method('concreteMethod')
->will($this->returnValue(2));
$this->assertSame(2, $stub->concreteMethod()); // Succeeds
}
/**
* Similar to above, but using getMockForAbstractClass().
* Apparently, setMethods() is ignored by getMockForAbstractClass()
*/
public function testConcreteMethod__mockBuilder_getMockForAbstractClass() {
$stub = $this->getMockBuilder('AbstractClass')
->setMethods(array('concreteMethod'))
->getMockForAbstractClass();
$stub->expects($this->any())
->method('concreteMethod')
->will($this->returnValue(2));
$this->assertSame(2, $stub->concreteMethod()); // Fails, concreteMethod returns NULL
}
}
推荐答案
我在基本测试用例中重写了getMock()
,以添加所有抽象方法,因为您必须始终对它们进行模拟.毫无疑问,您可以与建造者做类似的事情.
I override getMock()
in my base test case to add in all abstract methods because you must mock them all anyway. You could do something similar with the builder no doubt.
重要提示:您无法模拟私有方法.
Important: You cannot mock private methods.
public function getMock($originalClassName, $methods = array(), array $arguments = array(), $mockClassName = '', $callOriginalConstructor = TRUE, $callOriginalClone = TRUE, $callAutoload = TRUE) {
if ($methods !== null) {
$methods = array_unique(array_merge($methods,
self::getAbstractMethods($originalClassName, $callAutoload)));
}
return parent::getMock($originalClassName, $methods, $arguments, $mockClassName, $callOriginalConstructor, $callOriginalClone, $callAutoload);
}
/**
* Returns an array containing the names of the abstract methods in <code>$class</code>.
*
* @param string $class name of the class
* @return array zero or more abstract methods names
*/
public static function getAbstractMethods($class, $autoload=true) {
$methods = array();
if (class_exists($class, $autoload) || interface_exists($class, $autoload)) {
$reflector = new ReflectionClass($class);
foreach ($reflector->getMethods() as $method) {
if ($method->isAbstract()) {
$methods[] = $method->getName();
}
}
}
return $methods;
}
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