问题描述
我再次从Windows迁移到Linux，我必须将Windows移植到计算NTP时间的函数.看起来很简单，但格式为Windows FILETIME格式.我有点知道有什么区别，但是到目前为止，我无法正确地将Linux时间转换为Windows filetime格式.有人对如何执行此操作有任何想法吗?
I am once again going from Windows to Linux, I have to port a function from Windows to Linux that calculates NTP time. Seems simple but the format is in Windows FILETIME format. I sort of have an idea what the differences are but so far I can not correctly convert my Linux time to the windows filetime format. Does anyone have any ideas on how to do this?
我看过一些有关如何执行此操作的文章，但是它们都使用win32函数，而我不能使用它们！如果没有意义，我可以发布Windows代码，谢谢.
I have seen some articles on how to do this but they all use win32 functions and I can't use them! I can post the windows code if this makes no sense, thanks.
他们还采用当前时间，并从1900年1月1日开始将其减去以获得NTP的增量，我想在Linux中我只是将const unsigned long EPOCH = 2208988800UL加到我的时间上以获得此结果?
They also take the current time and subtract it from January 1st 1900 to get the delta to find NTP, I would assume in Linux I just add the const unsigned long EPOCH = 2208988800UL to my time to get this result?
谢谢.
推荐答案
这篇关于将Unix/Linux时间转换为Windows FILETIME的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！FILETIME 结构说明了它的含义.基本想法是，Windows FILETIME从1月1日1601开始以10 秒(100纳秒的间隔)进行计数(为什么1601?不知道...).在Linux中，您可以使用#include <sys/time.h>
/**
* number of seconds from 1 Jan. 1601 00:00 to 1 Jan 1970 00:00 UTC
*/
#define EPOCH_DIFF 11644473600LL
unsigned long long
getfiletime() {
struct timeval tv;
unsigned long long result = EPOCH_DIFF;
gettimeofday(&tv, NULL);
result += tv.tv_sec;
result *= 10000000LL;
result += tv.tv_usec * 10;
return result;
}