使用python从CSV创建字典

问题描述

我有一个CSV格式

其中A，B& C是标题.

where A, B & C are the headers.

我如何将该CSV Python转换为以下形式的字典

How do I pythonically convert this CSV into a dictionary of the following form

{'A': '1', 'B': '4','C': '7'},
{'A': '2', 'B': '5','C': '8'},
{'A': '3', 'B': '6','C': '9'}

到目前为止，我正在尝试以下代码:

So far I'm trying the following code:

import csv
reader = csv.DictReader(open('file.csv'))

result = {}
for row in reader:
    for column, value in row.items():
        result.setdefault(column, []).append(value)

这没有给我预期的输出.有什么建议吗?

This is not giving me the intended output. Any suggestions?

推荐答案

您没有多余的代码. csv已经为您完成了繁重的工作.只需按原样使用csv.DictReader:

The extra code you have is unnecessary. csv already does the heavy-lifting for you. Just use csv.DictReader as is:

import csv

with open('e.txt') as file:
    reader = csv.DictReader(file)
    for row in reader:
        print(row)

以上输出:

OrderedDict([('A', '1'), (' B', ' 4'), (' C', ' 7')])
OrderedDict([('A', '2'), (' B', ' 5'), (' C', ' 8')])
OrderedDict([('A', '3'), (' B', ' 6'), (' C', ' 9')])

您可能认为您想要的是dict而不是OrderedDict，但是我很确定您不需要.使用OrderedDict对象将确保您的行保持正确的顺序.

You may think you want a dict rather than an OrderedDict, but I'm fairly sure you don't. Using an OrderedDict object will ensure that your rows stay ordered correctly.

为什么呢?不要被格式所迷惑. OrderedDict 具有与常规词典相同的完全 .唯一的区别是OrderedDict将保持其顺序.如果只需要以某种格式打印行，则可以将每行转换为dict并使用它的__repr__:

Why exactly? Don't be fooled by the format. OrderedDict behaves the exact same as a normally dictionary. The only difference is that OrderedDict will maintain its order. If all you need is to print your rows in a certain format, you can convert each row to a dict and use it's __repr__:

for row in reader:
    print(dict(row))

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