C＃的WinForms MouseHover和鼠标离开的问题

问题描述

由于某种原因MouseHover和鼠标离开函数的行为真的很奇怪。所有我需要做的是，当光标在按钮，我想使按钮可见，当光标离开按钮，我想使它不可见。无论我尝试我不能使它工作。这似乎是在控制对象是无形的不工作的鼠标事件。

 私人无效button1_MouseHover（对象发件人，EventArgs的发送）
{
   button1.Visible = TRUE;
}私人无效button1_MouseLeave（对象发件人，EventArgs的发送）
{
    button1.Visible = FALSE;
}
 

解决方案

好吧......这是它如何工作的。继续处理按钮的鼠标离开事件和处理的MouseMove 其父（我假设的形式）：

 私人无效Form_MouseMove（对象发件人，MouseEventArgs E）{
    如果（button1.Bounds.Contains（e.Location）及＆放大器;！button1.Visible）{
        button1.Show（）;
    }
}
 

For some reason MouseHover and MouseLeave functions behave really strange. All I need to do is, when the cursor is over the "button", I want to make the button visible and when the cursor leaves the button, I want to make it invisible. Whatever I try I couldn't make it work. It seems like Mouse events not working when the control object is invisible.

private void button1_MouseHover(object sender, EventArgs e)
{
   button1.Visible = true;
}

private void button1_MouseLeave(object sender, EventArgs e)
{
    button1.Visible = false;
}

解决方案

Well... that's how it works. Continue handling the button's MouseLeave event and handle MouseMove for its parent (I assume the form):

private void Form_MouseMove(object sender, MouseEventArgs e) {
    if(button1.Bounds.Contains(e.Location) && !button1.Visible) {
        button1.Show();
    }
}

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