数字ex 9 + 8 = 17的数字之和应该是1 + 7 = 8应答

问题描述

我需要帮助来计算一些大于9的数字。



例如： - 如果我计算 9 + 8 = 17 的总和，我想再次将它们压缩成单个数字再次添加它们请帮帮我。



我申请了

Hi,

I need help to calculate some of digits of number greater than 9.

For example :- If I calculate sum of 9 + 8 = 17, again I want to condense this some into single digit by adding them again please help me in this.

I have applied

while(number!=0)
{
rem=number%10;
sum=sum+rem;
number=number/10;
}

这很好，但我想把它压缩成一位数。

This is fine, but I want to condense it into single digit.

推荐答案

dr(n) =
         0          if n == 0
         9          if n != 0 and n is divisable by 9
         n mod 9    in all other cases

请参阅 []

这使得实现该功能变得非常容易，即使不使用循环：

see Wikipedia:Digital Root[^]
That makes it really easy to implement that function, even without using a loop:

int DigitalRoot (int n)
{
  if (n == 0)
    return 0;
  else
  {
    int m = n % 9;
    return (m == 0) ? 9 : m;
  }
}

int reducer(int number)
{
    int sum = 0;
    while(number != 0)
    {
        rem = number % 10;
        sum += rem;
        number /= 10;
    }
    if (sum > 10)
        sum = reducer(sum);

    return sum;
}

#include<stdio.h>

void main()
{
    int num1, num2, number , sum = 0, rem = 0, count = 0, next = 0;

    printf("Enter two nos");
    scanf("%d %d", &num1, &num2);

    number = num1 + num2;

    if(number == 0)
    {
        printf("Sum: %d", sum);
    }

    for( ;number != 0; )
    {
        //finding the sum of the digits of the sum of the origional numbers
        while(number != 0)/
        {
            rem = number % 10;
            sum = sum + rem;
            number = number / 10;
        }

        next = sum;

        //checking the no of digits of the sum calculated in the above while loop
        while(next != 0)
        {
            rem = number % 10;
            next = next / 10;
            count++;
        }

        //if the digit is single then the number is printed
        if(count == 1)
        {
            printf("Sum: %d", sum);

            //go out of the loop
            break;
        }
        //if the no has more than 1 digits,then some variables  are  changed and as per next ,it's already 0 in the second for loop
        else
        {
            number = sum;
            sum = 0;
            count = 0;
        }
    }
}

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