将pandas DateTimeIndex转换为Unix时间?

问题描述

将熊猫的DateTimeIndex转换为Unix时间(可迭代)的惯用方式是什么?这可能不是要走的路:

What is the idiomatic way of converting a pandas DateTimeIndex to (an iterable of) Unix Time?This is probably not the way to go:

[time.mktime(t.timetuple()) for t in my_data_frame.index.to_pydatetime()]

推荐答案

由于DatetimeIndex是ndarray的内幕，因此您无需费解即可进行转换(快得多).

As DatetimeIndex is ndarray under the hood, you can do the conversion without a comprehension (much faster).

In [1]: import numpy as np

In [2]: import pandas as pd

In [3]: from datetime import datetime

In [4]: dates = [datetime(2012, 5, 1), datetime(2012, 5, 2), datetime(2012, 5, 3)]
   ...: index = pd.DatetimeIndex(dates)
   ...:
In [5]: index.astype(np.int64)
Out[5]: array([1335830400000000000, 1335916800000000000, 1336003200000000000],
        dtype=int64)

In [6]: index.astype(np.int64) // 10**9
Out[6]: array([1335830400, 1335916800, 1336003200], dtype=int64)

%timeit [t.value // 10 ** 9 for t in index]
10000 loops, best of 3: 119 us per loop

%timeit index.astype(np.int64) // 10**9
100000 loops, best of 3: 18.4 us per loop

这篇关于将pandas DateTimeIndex转换为Unix时间?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！