PHP的-取消链接抛出错误:资源暂时不可用

问题描述

这是一段代码:

public function uploadPhoto(){
    $filename = '../storage/temp/image.jpg';
    file_put_contents($filename,file_get_contents('http://example.com/image.jpg'));
    $photoService->uploadPhoto($filename);
    echo("If file exists: ".file_exists($filename));
    unlink($filename);
}

我正在尝试做以下事情:

I am trying to do the following things:

1. 从URL获取照片，并将其保存在服务器的临时文件夹中.这很好.创建图像文件，并在echo("If file exists: ".file_exists('../storage/temp/image.jpg'));时回显If file exists: 1.
2. 将该文件传递给另一个函数，该函数将文件上传到Amazon s3存储桶.该文件存储在我的s3存储桶中.
3. 删除存储在temp文件夹中的照片. 这行不通！我收到一条错误消息:

1. Get a photo from a URL and save it in a temp folder in my server. This works fine. The image file is created and echoes If file exists: 1 when echo("If file exists: ".file_exists('../storage/temp/image.jpg'));.
2. Pass that file to another function that hanldes uploading the file to Amazon s3 bucket. The file gets stored in my s3 bucket.
3. Delete the photo stored in the temp folder. This doesn't work! I get an error saying:

如果我使用rename($filename,'../storage/temp/renimage.jpg');而不是unlink($filename);，则会收到错误消息:

If I use rename($filename,'../storage/temp/renimage.jpg'); instead of unlink($filename); i get an error:

如果我删除函数调用$photoService->uploadPhoto($filename);，则一切正常.

If I remove the function call $photoService->uploadPhoto($filename);, everything works perfectly fine.

如果该文件正在被另一个进程使用，那么在该进程完成并且该文件不再被任何进程使用后，如何取消链接?我不想使用计时器.

If the file is being used by another process, how do I unlink it after the process has been completed and the file is no longer being used by any process? I do not want to use timers.

请帮助！预先感谢.

推荐答案

只需处理类似的错误.

您的$photoService似乎由于某种原因而保留了该图像...既然您没有共享$photoService的代码，我的建议是做这样的事情(假设您不再需要$photoService):

It seems your $photoService is holding on to the image for some reason...Since you didn't share the code of $photoService, my suggestion would be to do something like this (assuming you don't need $photoService anymore):

[...]
echo("If file exists: ".file_exists($filename));
unset($photoService);
unlink($filename);
}

unset()方法将销毁给定的变量/对象，因此它不能使用"(或无论如何使用)任何文件.

The unset() method will destroy the given variable/object, so it can't "use" (or wharever it does) any files.

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