本文介绍了fstream 不会创建文件的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

如果文本文件不存在,我只是想创建一个文本文件,而且我似乎无法让 fstream 做到这一点.

I'm simply trying to create a text file if it does not exist and I can't seem to get fstream to do this.

#include <fstream>
using std::fstream;

int main(int argc, char *argv[]) {
    fstream file;
    file.open("test.txt");
    file << "test";
    file.close();
}

我是否需要在 open() 函数中指定任何内容才能让它创建文件?我已经读到你不能指定 ios::in ,因为这会期望一个已经存在的文件在那里,但我不确定是否需要为一个文件指定其他参数不存在.

Do I need to specify anything in the open() function in order to get it to create the file? I've read that you can't specify ios::in as that will expect an already existing file to be there, but I'm unsure if other parameters need to be specified for a file that does not already exist.

推荐答案

你应该像这样添加 fstream::out 到 open 方法:

You should add fstream::out to open method like this:

file.open("test.txt",fstream::out);

有关 fstream 标志的更多信息,请查看此链接:http://www.cplusplus.com/reference/fstream/fstream/open/

More information about fstream flags, check out this link: http://www.cplusplus.com/reference/fstream/fstream/open/

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08-04 00:18