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问题描述
是否有可能用列明智地填充表中的值。例如
Is it possible to fill table with values in column wise. For example
<?php
echo "<table>";
for ($j=0;$j<6;$j++)
{
echo "<tr>";
for ($i=0;$i<6;$i++)
{
echo "<td>".$j.$i."</td>";
}
echo "</tr>";
}
echo "</table>";
?>
输出成为
The output becomes
00 01 02 03 04 05
10 11 12 13 14 15
20 21 22 23 24 25
30 31 32 33 34 35
40 41 42 43 44 45
50 51 52 53 54 55
但我希望桌子看起来像
00 10 20 30 40 50
01 11 21 31 41 51
02 12 22 32 42 52
03 13 23 33 43 53
04 14 24 34 44 54
05 15 25 35 45 55
我通过不改变填入表中的值来满足条件。 (改变从$ j。$ i到$ i的回声。$ j带来了这种外观,但是我想以列的方式填充数据)。它如何成为可能?
I came with up with a condition by not changing values that fill in the table. (Altering echo from $j.$i to $i.$j brings that appearance but i wanted to fill data in column wise). How it become possible?
推荐答案
下面是你真正做到这一点,老派风格,完全评论解释。 >
Here's how you really do it, old-school style, fully commented for explanation.
<?php
//NOTE: This excercise would be slightly easier if you just used php's DomDocument class because you wouldn't
//need to waste some logic determining whether to open/close the table rows, but here it is just echoing
//out some straight html
//The example data
$data_set = array("a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z");
//at the very least, you'll need to know how many columns you want to format the data into...
$number_of_columns = 5;
//count the data items
$number_of_data_items=count($data_set);
//determine how many rows you'll need to display the data in the given number of columns
$num_rows=ceil($number_of_data_items/$number_of_columns);
//determine exactly how many cells it will take to display the data
$num_cells=$num_rows*$number_of_columns;
//now that we have enough info to output the table...
//init some counters
$row_count=0;
$column_count=0;
//open the table element
echo "<table border='1' cellspacing='0' cellpadding='5'>";
for($i=0;$i<$num_cells;$i++){
$column_count++;
$index = $row_count + ($num_rows * ($column_count-1) );
if( $column_count==1 ){
echo "<tr>";
}
if( $index < $number_of_data_items){
echo "<td>Item :".($index+1)."</td>"; //Display the number of the data item we are
echo "<td>".$data_set[$index]."</td>"; //Display the actual data item
echo "<td> </td>"; //Add some extra space between columns
}else{
//write empty cells if the data set doesn't completely fill the last column
echo "<td> </td>";
echo "<td> </td>";
echo "<td> </td>";
}
if($number_of_columns == $column_count){
echo "</tr>";
$row_count++;
$column_count=0;
}
}
//close the table element
echo "</table>";
?>
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