本文介绍了WebRTC无法添加ICE候选人的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试与两个对等方建立p2p音频/视频连接。以下:。
I am trying to establish a p2p audio/video connection b/w two peers. Following: Getting started with WebRTC.
它可以在2台电脑之间的局域网环境中正常工作,但在我公司的局域网环境中运行
时会抛出错误信息,部分是javascript
It works fine at my home in LAN Environment between 2 PCs, but throws an error message when running at my company's LAN Environment, there is part the javascript
function processSignalingMessage(message) {
var msg = JSON.parse(message);
if (msg.type === 'offer') {
// Callee creates PeerConnection
if (!initiator && !started)
maybeStart();
// We only know JSEP version after createPeerConnection().
if (isRTCPeerConnection)
pc.setRemoteDescription(new RTCSessionDescription(msg));
else
pc.setRemoteDescription(pc.SDP_OFFER,
new SessionDescription(msg.sdp));
doAnswer();
} else if (msg.type === 'answer' && started) {
pc.setRemoteDescription(new RTCSessionDescription(msg));
} else if (msg.type === 'candidate' && started) {
var candidate = new RTCIceCandidate({
sdpMLineIndex : msg.label,
candidate : msg.candidate
});
pc.addIceCandidate(candidate);
} else if (msg.type === 'bye' && started) {
onRemoteHangup();
}
}
当第一个用户收到消息type时:候选人,出错了
when the first user recieved message "type":"candidate",get wrong
和部分控制台日志:
- 创建PeerConnection
- 使用config{iceServers创建了webkitRTCPeerConnnection:[{url:stun:stun.l.google.com:19302}]}
- 添加本地流
- 向同行发送答案
- 收到的消息:{type:candidate,label :0,id:audio,candidate:a =候选人:1613033416 1 udp 2113937151 192.168.1.233 56946 typ host generation 0 \\ n}
- Uncaught SyntaxError:无法在'RTCPeerConnection'上执行'addIceCandidate':无法添加ICE候选人
- 收到的消息:{type:candidat...... 。}
- 未捕获的SyntaxError:无法在'RTCPeerConnection'上执行'addIceCandidate':无法添加ICE候选者
- 收到的消息:{键入 : candidat .... ...}
- 未捕获的SyntaxError:无法在'RTCPeerConnection'上执行'addIceCandidate':无法添加ICE候选项
- Creating PeerConnection
- Created webkitRTCPeerConnnection with config "{"iceServers":[{"url":"stun:stun.l.google.com:19302"}]}"
- Adding local stream
- Sending answer to peer
- recieved message : {"type":"candidate","label":0,"id":"audio","candidate":"a=candidate:1613033416 1 udp 2113937151 192.168.1.233 56946 typ host generation 0\r\n"}
- Uncaught SyntaxError: Failed to execute 'addIceCandidate' on 'RTCPeerConnection': The ICE candidate could not be added
- recieved message : {"type":"candidat".......}
- Uncaught SyntaxError: Failed to execute 'addIceCandidate' on 'RTCPeerConnection': The ICE candidate could not be added
- recieved message : {"type":"candidat".......}
- Uncaught SyntaxError: Failed to execute 'addIceCandidate' on 'RTCPeerConnection': The ICE candidate could not be added
推荐答案
我认为你可以只使用msg.candidate创建ICE候选消息,
I think you can create the ICE candidate message by using just the msg.candidate,
var candidate = new RTCIceCandidate(msg.candidate);
并将其传递到 addIceCandidate
函数
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