如何从命令行启动JUnit 5（平台）（没有Maven / Gradle）？

问题描述

我想从命令行运行一个包含JUnit 5测试的类。不幸的是，我有一些外部依赖项阻止我使用Maven，Gradle或其他构建系统。

I'd like to run a class containing JUnit 5 tests from the command line. Unfortunately, I have some outside dependencies that prevent me from using Maven, Gradle, or other build systems.

在JUnit 4中，我可以像

In JUnit 4, I could accomplish this like

java .:"lib/*" org.junit.runner.JUnitCore TestClass

JUnit 5是否有等价物？我只想知道测试是否成功与在IntelliJ中运行时相似。

Is there an equivalent for JUnit 5? I'd simply like to know if test succeeded similar to when it runs in IntelliJ.

TestClass.java

TestClass.java

import org.junit.jupiter.api.AfterEach;
import org.junit.jupiter.api.BeforeAll;
import org.junit.jupiter.api.BeforeEach;
import org.junit.jupiter.api.Test;

import java.util.ArrayList;
import java.util.Collections;

import static org.junit.jupiter.api.Assertions.*;

public class TestClass {

    private static ArrayList<Student> students;
    private static ArrayList<Student> inAgeOrderStudents;
    private static ArrayList<Student> inNameOrderStudents;

    @BeforeAll
    static void setUp(){
        initializeStudents();
        initSortedAgeStudents();
        initSortedNameStudents();
    }

    @BeforeEach
    void reloadStudents() {
        Collections.shuffle(students);
    }

   static void initializeStudents(){
        students = new ArrayList<Student>();

        students.add(new Student(18, "Tim"));
        students.add(new Student(18, "Tim"));
        students.add(new Student(16, "Jean"));
        students.add(new Student(14, "Lin"));
        students.add(new Student(19, "Sam"));
    }

    static void initSortedAgeStudents(){
        inAgeOrderStudents = new ArrayList<Student>();
        inAgeOrderStudents.add(new Student(14, "Lin"));
        inAgeOrderStudents.add(new Student(16, "Jean"));
        inAgeOrderStudents.add(new Student(18, "Tim"));
        inAgeOrderStudents.add(new Student(18, "Tim"));
        inAgeOrderStudents.add(new Student(19, "Sam"));
    }

    static void initSortedNameStudents(){
        inNameOrderStudents = new ArrayList<Student>();
        inNameOrderStudents.add(new Student(16, "Jean"));
        inNameOrderStudents.add(new Student(14, "Lin"));
        inNameOrderStudents.add(new Student(19, "Sam"));
        inNameOrderStudents.add(new Student(18, "Tim"));
        inNameOrderStudents.add(new Student(18, "Tim"));
    }



    @Test
    void testMergeSort() {
        assertNotEquals(students, inAgeOrderStudents);
        StudentSortSearch.mergesort(students,StudentSortSearch.SortSearchCriteria.AGE);
        assertEquals(14,students.get(0).getAge());
        assertEquals(19,students.get(4).getAge());
        assertEquals(students, inAgeOrderStudents);

        assertEquals(true,students.equals(inAgeOrderStudents));
    }

    @Test
    void testQuickSort() {
        StudentSortSearch.quickSort(students,StudentSortSearch.SortSearchCriteria.NAME);
        assertEquals("Jean",students.get(0).getName());
        assertEquals("Tim",students.get(4).getName());

        assertEquals(students, inNameOrderStudents);
    }

    @Test
    void testBinarySearch() {
        StudentSortSearch searcher = new StudentSortSearch();
        ArrayList<Student> searchResults = searcher.binarySearch(students, 18);
        assertEquals(2, searchResults.size());
        assertEquals(18,searchResults.get(1).getAge());
        assertEquals(18,searchResults.get(0).getAge());

        searchResults = searcher.binarySearch(students, "Lin");
        assertEquals(1, searchResults.size());
        assertEquals(14,searchResults.get(0).getAge());
    }
}

推荐答案

当然，使用 ConsoleLauncher 。

包含所有
依赖项的可执行文件 * junit-platform-console-standalone-< version> .jar * 发布在目录。你可以运行
独立的ConsoleLauncher，如下所示。

An executable *junit-platform-console-standalone-<version>.jar* with all dependencies included is published in the central Maven repository under the junit-platform-console-standalone directory. You can run the standalone ConsoleLauncher as shown below.

java -jar junit-platform-console-standalone-<version>.jar <Options>

有关选项的详情，请参阅请。

For details about the options consult https://junit.org/junit5/docs/current/user-guide/#running-tests-console-launcher please.

为您的示例量身定制并使用JUnit Platform版本 1.3.1 ，命令可以看起来像这样：

Tailored to your example and using JUnit Platform version 1.3.1, the commands could look like those:

$ mkdir out
$ javac -d out Student.java StudentSortSearch.java
$ javac -d out -cp out:junit-platform-console-standalone-1.3.1.jar TestClass.java
$ java -jar junit-platform-console-standalone-1.3.1.jar --class-path out --scan-class-path
╷
├─ JUnit Jupiter ✔
│  └─ TestClass ✔
│     └─ test() ✔
└─ JUnit Vintage ✔

Test run finished after 67 ms
...

这篇关于如何从命令行启动JUnit 5（平台）（没有Maven / Gradle）？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！