如何在Python中使用BeautifulSoup从标记中提取innerHTML

问题描述

我正在尝试使用以下代码从标记中提取innerHTML:

I am trying to extract the innerHTML from a tag using the following code:

theurl = "http://na.op.gg/summoner/userName=Darshan"
thepage = urlopen(theurl)
soup = BeautifulSoup(thepage,"html.parser")
rank = soup.findAll('span',{"class":"tierRank"})

但是我却得到了[< span class="tierRank" > Master < /span >].我只想显示"Master"值.

However I am getting [< span class="tierRank" > Master < /span >] instead.What I want to show is the value "Master" only.

使用soup.get_text代替soup.findall不起作用.

我尝试将.text和.string添加到最后一行的末尾，但这也不起作用.

I tried adding .text and .string to the end of last line but that did not work either.

推荐答案

soup.findAll('span',{"class":"tierRank"})返回与<span class="tierRank">匹配的元素的列表.

soup.findAll('span',{"class":"tierRank"}) returns a list of elements that match <span class="tierRank">.

1. 您想要列表中的第一个元素.
2. 您想要该元素中的innerHtml，可以通过decode_contents()方法进行访问.

1. You want the first element from that list.
2. You want the innerHtml from that element, which can be accessed by the decode_contents() method.

一起:

rank = soup.findAll('span',{"class":"tierRank"})[0].decode_contents()

这会将"Master"存储在rank中.

This will store "Master" in rank.

这篇关于如何在Python中使用BeautifulSoup从标记中提取innerHTML的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！