问题描述
在 CodeReview 上，我发布了一段工作代码，并要求提供改进建议.我得到的一个是使用布尔方法来检查 ArrayList 是否具有偶数个索引(这是必需的).这是建议的代码:
On CodeReview I posted a working piece of code and asked for tips to improve it. One I got was to use a boolean method to check if an ArrayList had an even number of indices (which was required). This was the code that was suggested:
private static boolean isEven(int number)
{
return (number & 1) == 0;
}
因为我已经向那个特定的用户请求了很多帮助，所以我决定是时候向 SO 社区提出请求了！我真的不明白这是如何工作的.调用该方法并将 ArrayList 的大小作为参数(即 ArrayList 有 10 个元素，数量 = 10).
As I've already pestered that particular user for a lot of help, I've decided it's time I pestered the SO community! I don't really understand how this works. The method is called and takes the size of the ArrayList as a parameter (i.e. ArrayList has ten elements, number = 10).
我知道一个 & 会同时运行 number 和 1 的比较，但在那之后我迷路了.
I know a single & runs the comparison of both number and 1, but I got lost after that.
我读它的方式是，如果number == 0 和1 == 0，则返回true.我知道第一个不是真的，后者显然没有意义.有人可以帮我吗?
The way I read it, it is saying return true if number == 0 and 1 == 0. I know the first isn't true and the latter obviously doesn't make sense. Could anybody help me out?
我应该补充一点，代码确实有效，以防有人想知道.
推荐答案
记住&"是按位运算.您可能已经意识到这一点，但根据您提出问题的方式，我并不完全清楚.
Keep in mind that "&" is a bitwise operation. You are probably aware of this, but it's not totally clear to me based on the way you posed the question.
话虽如此，理论上的想法是你有一些 int，可以用一些 1 和 0 序列以位表示.例如:
That being said, the theoretical idea is that you have some int, which can be expressed in bits by some series of 1s and 0s. For example:
...10110110
在二进制中，因为它是基数 2，所以当数字的按位版本以 0 结尾时，它是偶数，当它以 1 结尾时，它是奇数.
In binary, because it is base 2, whenever the bitwise version of the number ends in 0, it is even, and when it ends in 1 it is odd.
因此，按位 &上面的 1 是:
Therefore, doing a bitwise & with 1 for the above is:
...10110110 & ...00000001
当然，这是0，所以你可以说原始输入是偶数.
Of course, this is 0, so you can say that the original input was even.
或者，考虑一个奇数.例如，在我们上面的内容上加 1.那么
Alternatively, consider an odd number. For example, add 1 to what we had above. Then
...10110111 & ...00000001
等于 1，因此不等于 0.瞧.
Is equal to 1, and is therefore, not equal to zero. Voila.
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