如何创建HTTP GET请求Scapy？

问题描述

我需要创建HTTP GET请求并保存数据响应。
我试图使用这个：

$ $ p $ code> syn = IP（dst = URL）/ TCP（dport = 80，flags ='S'）
syn_ack = sr1（syn）
getStr ='GET / HTTP / 1.1 \r\\\
Host：www.google.com\r\\\
\r\ n'
request = IP（dst ='www.google.com'）/ TCP（dport = 80，sport = syn_ack [TCP] .dport，
seq = syn_ack [TCP] .ack，ack = syn_ack [TCP] .seq + 1，flags ='A'）/ getStr
reply = sr1（request）
print reply.show（）

但是当我打印回复时，我没有看到任何数据响应。
另外，当我检查'Wireshark'时，我得到了SYN，SYN / ACK，但是我没有收到确认信。

Image：

编辑：

我现在试着去做：

 ＃从scapy.all导入scapy 
导入* 
 
＃打印信息标题
 print[*] ACK-GET示例 -  Thijs'Thice'Bosschert，06-06-2011
 
＃准备GET语句
 get ='GET / HTTP / 1.0 \\\
\\\
'
 
＃设置目标IP 
 ip = IP（dst =www.google.com）
 
＃生成随机源端口号
端口= RandNum（1024,65535）
 
＃创建SYN数据包
 SYN = ip / TCP（sport = port，dport = 80，flags =S， seq = 42）
 
＃发送SYN并接收SYN，ACK 
打印\\\
 [*]发送SYN数据包
 SYNACK = sr1（SYN）
 
＃使用GET请求创建ACK 
 ACK = ip / TCP（sport = SYNACK.dpor t，dport = 80，flags =A，seq = SYNACK.ack，ack = SYNACK.seq + 1）/ get 
 
＃发送ACK-GET请求
 print\\ \\ n [*]发送ACK-GET包
回复，错误= sr（ACK）
 
＃打印回复来自服务器
打印\\\
 [*]服务器：
 print reply.show（）
 
 print'\\\
 [*] Done！'
  

但它的打印回复来自服务器;

我需要基于行的文本数据：text / html。

解决方案

SYN并正确接收SYN_ACK。此时，您应根据您收到的SYN_ACK生成并发送ACK，然后最终传输HTTP GET请求。看起来你对TCP 3路握手机制有些困惑。总之，你不应该'得到'一个ACK，你应该自己生成并发送这个。

I need to create HTTP GET request and save the data response.I tried to use this:

    syn = IP(dst=URL) / TCP(dport=80, flags='S')
    syn_ack = sr1(syn)
    getStr = 'GET / HTTP/1.1\r\nHost: www.google.com\r\n\r\n'
    request = IP(dst='www.google.com') / TCP(dport=80, sport=syn_ack[TCP].dport,
            seq=syn_ack[TCP].ack, ack=syn_ack[TCP].seq + 1, flags='A') / getStr
    reply = sr1(request)
    print reply.show()

But when I print reply I don't see any data response.In addition, when I checked in 'Wireshark' I got SYN, SYN/ACK but I didn't get an ACK.

Image:

Edit:

I try to do that now:

# Import scapy
from scapy.all import *

# Print info header
print "[*] ACK-GET example -- Thijs 'Thice' Bosschert, 06-06-2011"

# Prepare GET statement
get='GET / HTTP/1.0\n\n'

# Set up target IP
ip=IP(dst="www.google.com")

# Generate random source port number
port=RandNum(1024,65535)

# Create SYN packet
SYN=ip/TCP(sport=port, dport=80, flags="S", seq=42)

# Send SYN and receive SYN,ACK
print "\n[*] Sending SYN packet"
SYNACK=sr1(SYN)

# Create ACK with GET request
ACK=ip/TCP(sport=SYNACK.dport, dport=80, flags="A", seq=SYNACK.ack, ack=SYNACK.seq + 1) / get

# SEND our ACK-GET request
print "\n[*] Sending ACK-GET packet"
reply,error=sr(ACK)

# print reply from server
print "\n[*] Reply from server:"
print reply.show()

print '\n[*] Done!'

but its print me in reply from server;

And I need Line-based text data: text/html.

解决方案

You are sending a SYN and correctly receiving a SYN_ACK. At this point, you should generate and send an ACK based on the SYN_ACK that you've received, and THEN finally transmit the HTTP GET request. It seems that you are somewhat confused about the TCP 3-way handshake mechanism. In short, you are not supposed to 'get' an ACK, you are supposed to generate and send this yourself.

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