本文介绍了如何将Python urllib.request代码转换为Java代码的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
这是python代码
import urllib.request as urllib2
import json
data = {
"Inputs": {
"input1": {
"ColumnNames": ["id", "regex"],
"Values": [ [ "0", "the regex value" ],]
},
},
"GlobalParameters": {
"Database query": "select * from expone",
}
}
body = str.encode(json.dumps(data))
url = 'https://ussouthcentral.services.azureml.net/workspaces/4729545551a741e1a2e606d37' \
'ae61ce0/services/ac7c34ad134d43ca9fdc65e292ce35d3/execute?api-version=2.0&details=true'
api_key = '8ku5P6fR3F8ykgMHK5Y8+PL8dn+Zi2Ajmwyjk9ENsomzzkDfuT8CtgKS7dF4yjaJfYxARe+1iLjh' \
'Tv1R0qOTvw=='
headers = {
'Content-Type': 'application/json',
'Authorization': ('Bearer '+ api_key)
}
req = urllib2.Request(url, body, headers)
try:
response = urllib2.urlopen(req)
result = response.read()
print(result)
except Exception as e:
print("The request failed with status code: ", e)
这是我在Java中的尝试
And this is my attempt in Java
public static void main(String[] args) {
System.out.println("MachineLearning main");
try{
//connections settings
URL url = new URL("https://ussouthcentral.services.azureml.net/workspaces/4729545551a741e1a2e606d37ae61ce0/services/ac7c34ad134d43ca9fdc65e292ce35d3/execute?api-version=2.0&details=true");
HttpURLConnection con = (HttpURLConnection)url.openConnection();
con.setDoInput(true);
con.setDoOutput(true);
String requestMethod = "GET";
con.setRequestMethod(requestMethod);
con.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
String data=URLEncoder.encode("input1", "UTF-8") + "="
+ URLEncoder.encode("\"ColumnNames\": [\"id\", \"regex\"]", "UTF-8") + "&"
+ URLEncoder.encode("GlobalParameters", "UTF-8")
+ URLEncoder.encode("Database query\": \"select * from expone\"", "UTF-8");
//make the request
OutputStreamWriter writer = new OutputStreamWriter(con.getOutputStream());
writer.write(data);
writer.flush();
//read the request
BufferedReader reader=new BufferedReader(new InputStreamReader(con.getInputStream()));
String response;
while ((response=reader.readLine())!=null)
System.out.println(response);
}
catch(Exception e) {
System.out.println("Exception in MachineLearning.main " + e);
}
}
java中请求的代码不成功,并返回异常:服务器返回的HTTP响应代码:URL的401
The code that is requested in java is not succesful and returns an exception:Server returned HTTP response code: 401 for URL
问题是我不知道如何将python中的数据变量转换为java中的数据变量,如何传递apiKey以及如何将其放入标头中?
Problem is that I don't know how to translate the data variable in python to that in java, and how do I pass the apiKey and how is that put in the headers?
推荐答案
您的Java代码中有几个小"bug":
You have several little 'bugs' in your java code :
- 将
setRequestMethod
更改为"POST" - 将"Content-Type"更改为"application/json"
- 添加新的
setRequestProperty
进行授权 - 不要对
data
进行urlencode
- Change
setRequestMethod
to "POST" - Change "Content-Type" to "application/json"
- Add a new
setRequestProperty
for authorization - Don't urlencode the
data
代码:
public static void main(String[] args) {
System.out.println("MachineLearning main");
try{
//connections settings
String api_key = "8ku5P6fR3F8ykgMHK5Y8+PL8dn+Zi2Ajmwyjk9ENsomzzkDfuT8CtgKS7dF4yjaJfYxARe+1iLjhTv1R0qOTvw==";
String data = "{\"Inputs\": {\"input1\": {\"ColumnNames\": [\"id\", \"regex\"], \"Values\": [[\"0\", \"the regex value\"]]}}, \"GlobalParameters\": {\"Database query\": \"select * from expone\"}}";
URL url = new URL("https://ussouthcentral.services.azureml.net/workspaces/4729545551a741e1a2e606d37ae61ce0/services/ac7c34ad134d43ca9fdc65e292ce35d3/execute?api-version=2.0&details=true");
HttpURLConnection con = (HttpURLConnection) url.openConnection();
con.setDoInput(true);
con.setDoOutput (true);
con.setRequestMethod("POST");
con.setRequestProperty("Content-Type", "application/json");
con.setRequestProperty("Authorization", "Bearer " + api_key);
//make the request
OutputStreamWriter writer = new OutputStreamWriter(con.getOutputStream());
writer.write(data);
writer.flush();
//read the request
BufferedReader reader=new BufferedReader(new InputStreamReader(con.getInputStream()));
String response;
while ((response=reader.readLine())!=null)
System.out.println(response);
} catch(Exception e) {
System.out.println("Exception in MachineLearning.main " + e);
}
}
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