本文介绍了解析整个向下滚动的网页的 html 代码的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
from bs4 import BeautifulSoup
import urllib,sys
reload(sys)
sys.setdefaultencoding("utf-8")
r = urllib.urlopen('https://twitter.com/ndtv').read()
soup = BeautifulSoup(r)
这不会让我把整个网页向下滚动到我想要的末尾,而只会滚动其中的一部分.
This would give me not the whole web page scrolled down the end which I want but only some of it.
from selenium import webdriver
from selenium.common.exceptions import StaleElementReferenceException, TimeoutException
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from bs4 import BeautifulSoup
import urllib,sys,requests
reload(sys)
sys.setdefaultencoding("utf-8")
class wait_for_more_than_n_elements_to_be_present(object):
def __init__(self, locator, count):
self.locator = locator
self.count = count
def __call__(self, driver):
try:
elements = EC._find_elements(driver, self.locator)
return len(elements) > self.count
except StaleElementReferenceException:
return False
def return_html_code(url):
driver = webdriver.Firefox()
driver.maximize_window()
driver.get(url)
# initial wait for the tweets to load
wait = WebDriverWait(driver, 10)
wait.until(EC.visibility_of_element_located((By.CSS_SELECTOR, "li[data-item-id]")))
# scroll down to the last tweet until there is no more tweets loaded
while True:
tweets = driver.find_elements_by_css_selector("li[data-item-id]")
number_of_tweets = len(tweets)
print number_of_tweets
driver.execute_script("arguments[0].scrollIntoView();", tweets[-1])
try:
wait.until(wait_for_more_than_n_elements_to_be_present((By.CSS_SELECTOR, "li[data-item-id]"), number_of_tweets))
except TimeoutException:
break
html_full_source=driver.page_source
driver.close()
return html_full_source
url='https://twitter.com/thecoolstacks'
#using selenium browser
html_source=return_html_code(url)
soup_selenium = BeautifulSoup(html_source)
print soup_selenium
text_tweet=[]
alltweets_selenium = soup_selenium.find_all(attrs={'data-item-type' : 'tweet'})
for tweet in alltweets_selenium:
#Text of tweet
html_tweet= tweet.find_all("p", class_="TweetTextSize TweetTextSize--16px js-tweet-text tweet-text")
text_tweet.append(''.join(html_tweet[0].findAll(text=True)))
print text_tweet
预期输出:
import requests from bs4 import BeautifulSoup url='https://twitter.com/thecoolstacks'
req = requests.get(url)
soup = BeautifulSoup(req.content)
alltweets = soup.find_all(attrs={'data-item-type' : 'tweet'})
print alltweets[0]
推荐答案
我仍然坚持使用 Twitter API.
或者,您可以通过以下方式解决 selenium
的问题:
Alternatively, here is how you can approach the problem with selenium
:
- use Explicit Waits and define a custom Expected Condition to wait for tweets to load on scroll
- perform the scroll to a last loaded tweet via
scrollIntoView()
实施:
from selenium import webdriver
from selenium.common.exceptions import StaleElementReferenceException, TimeoutException
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
class wait_for_more_than_n_elements_to_be_present(object):
def __init__(self, locator, count):
self.locator = locator
self.count = count
def __call__(self, driver):
try:
elements = EC._find_elements(driver, self.locator)
return len(elements) > self.count
except StaleElementReferenceException:
return False
url = "https://twitter.com/ndtv"
driver = webdriver.Firefox()
driver.maximize_window()
driver.get(url)
# initial wait for the tweets to load
wait = WebDriverWait(driver, 10)
wait.until(EC.visibility_of_element_located((By.CSS_SELECTOR, "li[data-item-id]")))
# scroll down to the last tweet until there is no more tweets loaded
while True:
tweets = driver.find_elements_by_css_selector("li[data-item-id]")
number_of_tweets = len(tweets)
driver.execute_script("arguments[0].scrollIntoView();", tweets[-1])
try:
wait.until(wait_for_more_than_n_elements_to_be_present((By.CSS_SELECTOR, "li[data-item-id]"), number_of_tweets))
except TimeoutException:
break
这将向下滚动到加载该频道中所有现有推文所需的范围.
This would scroll down as much as it is needed to load all of the existing tweets in this channel.
这是提取推文的 HTML 解析片段:
Here is the HTML-parsing snippet, extracting tweets:
page_source = driver.page_source
driver.close()
soup = BeautifulSoup(page_source)
for tweet in soup.select("div.tweet div.content"):
print tweet.p.text
它打印:
Father's Day Facebook post by arrested cop Suhas Gokhale's son got nearly 10,000 likes http://goo.gl/aPqlxf pic.twitter.com/JUqmdWNQ3c
#HWL2015 End of third quarter! Breathtaking stuff. India 2-2 Pakistan - http://sports.ndtv.com/hockey/news/244463-hockey-world-league-semifinal-india-vs-pakistan-antwerp …
Why these Kashmiri boys may miss their IIT dream http://goo.gl/9LVKfK pic.twitter.com/gohX21Gibi
...
这篇关于解析整个向下滚动的网页的 html 代码的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!