问题描述
我想在不使用整个文件路径的情况下从包中读取所有文件。例如，我可以使用这样的东西来获取目录中的所有文件。
I want to read all of the files from within my package without using my entire file path. For example I can use something like this to get all of the files in a dir.
new File("/Users/me/Documents/workspace/testing/src/main/java/resources/").listFiles()
当我在intellij中有一个看起来像这样的包时：
When I have a package in intellij that looks like this:
main
- java
--com.testFile
--resources
我读到这个：。但是我希望能够在不指定整个路径的情况下执行此操作。
I read this: Read file from a folder inside the project directory. However I want to be able to do this without specifying the the whole path.
例如，这里解释：
我以为我可以做类似
src / main / java / resources但我尝试的每个组合在插入时都会失败in to：
"src/main/java/resources" but every combination I try fails when plugged in to:
new File("/Users/me/Documents/workspace/testing/src/main/java/resources/").listFiles()
我可以发誓我之前做过这样的事吗？我犯了一个愚蠢的错误吗？
I could have sworn I've done this before like this? Am I making a silly mistake?
截至目前，它无法找到该文件。它是从java文件中的文件运行 - > com.thisproject / app
As of right now it can't locate the file. It's being run from a file in a file in java -> com.thisproject/app
例如我看到：
File folder = new File("src/");
File[] listOfFiles = folder.listFiles();
将listOfFiles设为null。
have listOfFiles be null.
推荐答案
解决了...
这实际上有点奇怪。我在网上找到的所有东西都说参考src / main等...这是我的文件路径。
Solved...This was actually kind of weird. Everything I found online said to reference src/main etc... Which is my file path.
但是我可以通过以下方式访问它：
However I was able to access it through:
new file("java/resources").listFiles();
哪个效果很好。如果我尝试以下任何组合：
Which works perfectly. If I were to try any of the below combinations:
new file("/java/resources").listFiles();
new file("main/java/resources").listFiles();
new file("src/main/java/resources").listFiles();
它们都失败了。
对于系统info我正在使用intellij，Mac OS，我正在开发一个intellij创建的webapp。不确定这是否有所作为。
For system info I'm using intellij, Mac OS, I'm working on a intellij created webapp. Not sure if that makes a difference.
如果有人知道为什么src / ...不起作用，我很想知道。
If anyone knows why src/... doesn't work I'd love to know.
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