本文介绍了如何使用 Stream 在集合中拆分奇数和偶数以及两者的总和的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
如何使用 Java 8 的流方法拆分奇数和偶数并在集合中求和?
How can I split odd and even numbers and sum both in a collection using stream methods of Java 8?
public class SplitAndSumOddEven {
public static void main(String[] args) {
// Read the input
try (Scanner scanner = new Scanner(System.in)) {
// Read the number of inputs needs to read.
int length = scanner.nextInt();
// Fillup the list of inputs
List<Integer> inputList = new ArrayList<>();
for (int i = 0; i < length; i++) {
inputList.add(scanner.nextInt());
}
// TODO:: operate on inputs and produce output as output map
Map<Boolean, Integer> oddAndEvenSums = inputList.stream(); // Here I want to split odd & even from that array and sum of both
// Do not modify below code. Print output from list
System.out.println(oddAndEvenSums);
}
}
}
推荐答案
你可以使用 Collectors.partitioningBy
完全符合您的要求:
You can use Collectors.partitioningBy
which does exactly what you want:
Map<Boolean, Integer> result = inputList.stream().collect(
Collectors.partitioningBy(x -> x%2 == 0, Collectors.summingInt(Integer::intValue)));
生成的映射包含 true
键中偶数的总和和 false
键中奇数的总和.
The resulting map contains sum of even numbers in true
key and sum of odd numbers in false
key.
这篇关于如何使用 Stream 在集合中拆分奇数和偶数以及两者的总和的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!