使用JSON数据发送数据从安卓到服务器

问题描述

我从Android应用程序与Web服务器试图发送数据。我的Andr​​oid应用程序正在successfully.However PHP code有问题。

I am trying sending data from Android application to web server. My android application is working successfully.However php code have problems.

<?php
$json = $_SERVER['HTTP_JSON'];
echo "JSON: \n";
var_dump($json);
echo "\n\n";

$data = json_decode($json,true);
echo "Array: \n";
var_dump($data);
echo "\n\n";

$name = $data['name'];
$pos = $data['position'];
echo "Result: \n";
echo "Name     : ".$name."\n Position : ".$pos;
?>

错误：

Notice: Undefined index: HTTP_JSON in C:\wamp\www\jsonTest.php on line 2
( line 2 : $json = $_SERVER['HTTP_JSON']; )

我无法找到这些问题的原因。你能帮助我吗 ？（注：我使用WAMP服务器）

I couldn't find these problems reason. Can you help me ?( note: I am using wamp server )

下面是有关Android源：

Here is the relevant Android source:

// Create a new HttpClient and Post Header
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("10.0.2.2:90/jsonTest.php";);

JSONObject json = new JSONObject();
try {
    json.put("name", "flower");
    json.put("position", "student");
    JSONArray postjson=new JSONArray();
    postjson.put(json);
    httppost.setHeader("json",json.toString());
    httppost.getParams().setParameter("jsonpost",postjson);
    System.out.print(json);
    HttpResponse response = httpclient.execute(httppost);

    if(response != null)
    {
    InputStream is = response.getEntity().getContent();

    BufferedReader reader = new BufferedReader(new InputStreamReader(is));
    StringBuilder sb = new StringBuilder();

    String line = null;
    try {
        while ((line = reader.readLine()) != null) {
            sb.append(line + "\n");
        }
        } catch (IOException e) {
        e.printStackTrace();
        } finally {
        try {
        is.close();
        } catch (IOException e) {
        e.printStackTrace();
        }
        }
    text = sb.toString();
    }
    tv.setText(text);

}catch (ClientProtocolException e) {
    // TODO Auto-generated catch block
} catch (IOException e) {
    // TODO Auto-generated catch block
}

这code成功的作品在Android上侧（无误差）。但是PHP端有问题..谢谢你。

This code works successfully on android side(no error). But php side has problems..Thanks.

推荐答案

这是不是在您的JSON是：

This isn't where your JSON is:

$json = $_SERVER['HTTP_JSON'];

您可能意味着：

$json = $_POST['HTTP_JSON'];

其中， HTTP_JSON 是你在你的Andr​​oid应用程序给你JSON的POST变量名。

Where HTTP_JSON is the POST variable name you gave to your JSON in your Android app.

错误的其余部分源于一个事实，即 json_de code 失败，因为你没有成功地从请求读取JSON数据。您可以检查 json_de $ C $了C 的反应来检查是否成功如下：

The rest of the errors stem from the fact that json_decode is failing because you're not successfully reading the JSON data from the request. You can check the response of json_decode to check if it was successful as follows:

$data = json_decode($json,true);
if( $data === NULL)
{
    exit( 'Could not decode JSON');
}

最后，通过真作为第二个参数 json_en code 意味着它会返回一个关联数组，所以你访问的元素，像这样：

Finally, passing true as the second parameter to json_encode means it will return an associative array, so you'd access elements like so:

$name = $data['name'];
$pos = $data['position'];

请确保您阅读文档为json_en code让你明白它做。

Make sure you read the docs for json_encode so you understand what it's doing.

编辑：您的问题是，你被错误的名称访问 $ _ POST 参数。你应该使用：

Your problem is that you're accessing the $_POST parameter by the wrong name. You should be using:

$json = $_POST['jsonpost'];

由于以下行命名的参数jsonpost：

Since the following line names the parameter "jsonpost":

httppost.getParams().setParameter("jsonpost",postjson);

这篇关于使用JSON数据发送数据从安卓到服务器的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！