显式类型转换（功能符号）和简单类型说明符

问题描述

移植一些代码我发现了这一行

  unsigned char uc = unsigned char（c）; 
  

被MSVC接受但被GCC拒绝。这个语法是否正确？

标准说明

这是否意味着MS正确？是 unsigned char 一个'简单类型说明符'？

解决方案

和是正确的，代码无效。

是单字型的名称：

unsigned char 不是简单类型说明符，而是组合 o f简单类型说明符，如
$ b

是来自cppreference.com的一个解释：

Porting some code I have discovered that line

unsigned char uc = unsigned char(c);

is accepted by MSVC but rejected by GCC. Is this syntax correct?
Standard says that

Does it mean that MS is right? Is unsigned char a 'simple-type-specifier'?

解决方案

GCC and CLANG are correct, the code is not valid.

Simple type specifier is single-word type name:

unsigned char is not a simple-type-specifier, it's a combination of simple-type-specifiers, as shown in Table 9 from standard.

Here's an explanation from cppreference.com:

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