删除volatile cv的原因是什么？

问题描述

const_cast 可用于删除 volatile 限定符：

The const_cast can be used to remove volatile qualifier:

Quote：

特别是，只有const_cast可用于抛弃（删除）constness或volatility

In particular, only const_cast may be used to cast away (remove) constness or volatility

[]



但 volatile 对象应该是 NOT 以这种方式访问​​：

const_cast conversion - cppreference.com[^]

But the volatile object should NOT be accessed that way:

Quote：

任何尝试引用volatile对象通过非易失性glvalue（例如通过引用或指向非易失性类型的指针）导致未定义的行为

Any attempt to refer to a volatile object through a non-volatile glvalue (e.g. through a reference or pointer to non-volatile type) results in undefined behavior

[]



那么，重点是什么？



此外，在我看来，从实际的 const 对象中删除 const cv（存储在标记为const的内存页面中）导致分段错误。



我尝试过：



我确认，当我试图通过 none volatile ref（使用<$ c）访问 volatile 对象时在 MS VS 2013 中的$ c> const_cast ）它运行良好，通过编译在 MS VS 2015 它只是粉碎了，所以是的，这显然是UB 。

cv (const and volatile) type qualifiers - cppreference.com[^]

So, what the point?

Also, as i see it, removing the const cv from an actual const object (stored in the memory page marked as const) leads to the segmentation fault.

What I have tried:

I confirm that, when i was trying to access the volatile object by none volatile ref (using the const_cast) in MS VS 2013 it works fine, through compiled in MS VS 2015 it just crushed, so yep this is clearly UB.

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