问题描述
我正在寻找一种将"1"显示为"01"的方法，因此基本上所有低于10的内容都应以0开头.
I'm looking for a way to display "1" as "01", so basically everything below 10 should have a leading 0.
什么是最好的方法?我知道我可以使用简单的if结构来执行此检查，但是使用NSNumberformatter应该可以做到这一点吧?
What would be the best way to do this?I know I can just use a simple if structure to do this check, but this should be possible with NSNumberformatter right?
推荐答案
如果您只想使用NSString，则只需执行以下操作:
If you just want an NSString, you can simply do this:
NSString *myNumber = [NSString stringWithFormat:@"%02d", number];
%02d来自C.％nd表示字符串中至少应包含n个字符，如果少于，请用0填充.这是一个示例:
The %02d is from C. %nd means there must be at least n characters in the string and if there are less, pad it with 0's. Here's an example:
NSString *example = [NSString stringWithFormat:@"%010d", number];
如果number变量只有两位数字，那么它将以八个零作为前缀.如果它是9位数字，则将以单个零作为前缀.
If the number variable only was two digits long, it would be prefixed by eight zeroes. If it was 9 digits long, it would be prefixed by a single zero.
如果要使用NSNumberFormatter，可以执行以下操作:
If you want to use NSNumberFormatter, you could do this:
NSNumberFormatter * numberFormatter = [[NSNumberFormatter alloc] init];
[numberFormatter setPaddingPosition:NSNumberFormatterPadBeforePrefix];
[numberFormatter setPaddingCharacter:@"0"];
[numberFormatter setMinimumIntegerDigits:10];
NSNumber *number = [NSNumber numberWithInt:numberVariableHere];
----更新------我认为这可以解决您的问题:
----UPDATE------I think this solves your problem:
[_minutes addObject:[NSNumber numberWithInt:i]];
return [NSString stringWithFormat:@"%02d", [[_minutes objectAtIndex:row] intValue]];
这篇关于NSNumberformatter加零的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！