问题描述
Objective-C中的& 符号是什么意思？我目前正在查看数据结构，并且我对此感到非常困惑。
What does the & symbol mean in Objective-C? I am currently looking at data constucts and am getting really confused by it.
我已经浏览了网页，但还没有找到答案。我知道这可能是一个基本的Objective-C概念，但我无法理解它。
I have looked around the web for it but have not found an answer at all. I know this is possibly a basic Objective-C concept, but I just can't get my head around it.
例如：
int *pIntData = (int *)&incomingPacket[0];
这里输入数据包的代码是什么？
What is the code doing with incoming packet here?
推荐答案
&是一元运算符的C地址。它返回其操作数的内存地址。
& is the C address-of unary operator. It returns the memory address of its operand.
在您的示例中，它将返回incomingPacket数组的第一个元素的地址，然后将其转换为int * （指向int的指针）
In your example, it will return the address of the first element of the incomingPacket array, which is then cast to an int* (pointer to int)
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