问题描述
我已经在Django中编写了一个测试，并且我正在。这是测试：
I have written a test in Django, and I'm using unittest.mock.ANY to ignore certain values in a dictionary. Here is the test:
from django.test import TestCase
from django.contrib.auth import get_user_model
import unittest.mock as mock
class Example(TestCase):
def test_example(self):
user = get_user_model().objects.create_user(username='example')
result = {'user': user, 'number': 42}
self.assertEqual(
result,
{'user': mock.ANY, 'number': 42}
)
如果我运行此测试，我希望它能通过。相反，我遇到了这种失败：
If I run this test, I expect it to pass. Instead, I get this failure:
======================================================================
FAIL: test_example (example.tests.Example)
----------------------------------------------------------------------
Traceback (most recent call last):
File "example/tests.py", line 18, in test_example
'number': 42,
AssertionError: {'user': <User: example>, 'number': 42} != {'user': <ANY>, 'number': 42}
- {'number': 42, 'user': <User: example>}
? ^^^^^^^^^^^^^
+ {'number': 42, 'user': <ANY>}
? ^^^
为什么不在这种情况下有效？
Why doesn't ANY work in this case? It seems to work with strings and numbers.
推荐答案
assertEqual ，在在比较两个参数的过程中，计算表达式 user ==模拟.ANY 。以标准方式， left 参数确定哪个函数实际实现 == 。在这种情况下，您有 user .__ eq __（mock.ANY）。看来无论 user 是什么类型，其 __ eq __ 方法仅返回 False 表示意外类型。如果它引发了 NotImplemented ，则该语言将落在 mock.ANY .__ eq __（user）上，这可能会返回 True 。
assertEqual, in the course of comparing its two arguments, evaluates the expression user == mock.ANY. In standard fashion, the left argument determines which function actually implements ==. In this case, you have user.__eq__(mock.ANY). It appears that whatever type user is, its __eq__ method simply returns False for an unexpected type. If it raised NotImplemented instead, the language would fall back on mock.ANY.__eq__(user), which could return True.
如果将通话更改为
self.assertEqual(
{'user': mock.ANY, 'number': 42},
result,
)
然后得到的比较结果 mock.ANY ==用户将返回 True 如预期。
then the resulting comparison mock.ANY == user will return True as expected.
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