两个构造函数，这是默认的？

问题描述

好吧，我有一个很简单的任务。

Okay I got a pretty simple assignment.

我有两个类Person的构造函数：

I got these two constructors for class Person:

Person( const string &, const string &, const string & );
Person( const string &, const string &, const string &,
const string & );

我有4个默认值

这些都将是默认构造函数？是

which of these are going to be the default constructor? is it always the one with most arguments or how does it work?

推荐答案

根据C ++标准

从您的帖子中不清楚您正在讲什么默认值。

From your post it is not clear what default values you are speaking about. Neither of your declarations is the default constructor.

如果你是在声明中使用默认参数

If you are speaking about default arguments as in the declaration

Person( const string & = "", const string & = "", const string & = "",
const string & = "" );

然后这个声明是一个默认构造函数的声明，因为它可以被调用没有任何明确指定的参数。

Then this declaration is a declaration of the default constructor because it can be called without any explicitly specified argument.

有趣的是，同一个构造函数可以同时是一个默认构造函数和一个非默认构造函数。至少C ++标准不会说任何禁止这个。

It is interesting to note that the same constructor can be a default constructor and a non-default constructor at the same time. At least the C++ Standard does not say anything that forbids this.

例如

struct A
{
   A( int x );
   int x;
};

A a1; // error: there is no default constructor

A::A( int x = 0 ) : x( x ) {}

A a2; // well-formed there is a default constructor.

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