在两个构造函数之间进行选择

问题描述

问题：我有一个具有两个构造函数的不可复制对象。我需要创建一个对象与一个构造函数，然后在一些常见的代码中使用它： -

Problem: I have a non-copyable object with two constructors. I need to create an object with one of the constructors and then use it within some common code:-

对于可复制对象，它将看起来像这样，

With a copyable object it would look like this, and be easy:

Object a;

if (condition)
   a = Object(p1);
else
   a = Object(p2,p3,p4);

a.doSomething();

但是，对象是不可复制的，所以我不得不这样做：

But, the object is non-copyable, so I've had to do this:

boost::scoped_ptr<Object> a;

if (condition)
   a = new Object(p1);
else
   a = new Object(p2,p3,p4);

a->doSomething();

这太麻烦了。有没有更好的解决方案？

This feels too complex. Is there a better solutiuon?

推荐答案

这是一个非常可怕的黑客，假设 Object 是默认可构造的：

Here's a very terrible hack, assuming Object is default-constructible:

Object a;
a.~Object();

if (condition) { ::new (&a) Object(p1); }
else           { ::new (&a) Object(p2, p3, p4); }

（使用）。 （感谢@ K-Ballo挖掘细节！）

A cleaner solution could be achieved with Boost.Optional (using in-place factories). (Thanks to @K-Ballo for digging up the details!)

#include <boost/optional.hpp>
#include <boost/utility/in_place_factory.hpp>

struct Object
{
    explicit Object(int) {}
    explicit Object(int, float, std::string) {}

    Object(Object const &)             = delete;
    Object(Object &&)                  = delete;
    Object & operator=(Object const &) = delete;
    Object & operator=(Object &&)      = delete;
};

boost::optional<Object> a;

if (condition) { a = boost::in_place(0); }
else           { a = boost::in_place(0, 1.0f, "two" ); }

这篇关于在两个构造函数之间进行选择的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！