php检查文件名是否存在

php检查文件名是否存在

本文介绍了php检查文件名是否存在,重命名该文件的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

如何检查文件名是否存在,重命名文件?

How do I check if file name exists, rename the file?

例如,如果文件存在,我上传图像1086_002.jpg,将文件重命名为1086_0021.jpg并保存,如果1086_0021.jpg存在,则重命名1086_00211.jpg并保存,如果1086_00211.jpg存在,则重命名1086_002111.jpg并保存...

for example, I upload a image 1086_002.jpg if the file exists, rename the file as 1086_0021.jpg and save, if 1086_0021.jpg is exist, rename 1086_00211.jpg and save , if 1086_00211.jpg is exist, rename 1086_002111.jpg and save...

这是我的代码,仅当1086_002.jpg存在时才能执行,将文件重命名为1086_0021.jpg,也许应该执行一次foreach,但是如何?

Here is my code, it only can do if 1086_002.jpg exist, rename the file as 1086_0021.jpg, maybe should do a foreach, but how?

//$fullpath = 'images/1086_002.jpg';

if(file_exists($fullpath)) {
    $newpieces = explode(".", $fullpath);
    $frontpath = str_replace('.'.end($newpieces),'',$fullpath);
    $newpath = $frontpath.'1.'.end($newpieces);
}

file_put_contents($newpath, file_get_contents($_POST['upload']));

推荐答案

尝试类似的方法:

$fullpath = 'images/1086_002.jpg';
$additional = '1';

while (file_exists($fullpath)) {
    $info = pathinfo($fullpath);
    $fullpath = $info['dirname'] . '/'
              . $info['filename'] . $additional
              . '.' . $info['extension'];
}

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08-01 01:34