如何动态分配通用类型

本文介绍了如何动态分配通用类型的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

通用类:

Generic class:

public class GenericEntityMapping
{
    public T Map<t>(XmlNode xNode, T entityObject)
    {
        //FYI.
        //PropertyInfo[] entityProperties = typeof(T).GetProperties();
        //foreach (PropertyInfo pInfo in entityProperties){...}

        //somewhere in the code depends on the condition.
        if true then...
        GenericEntityMapping<SampleEntity01>.Map(node, new SampleEntity01())
        .
        .
        .
        else if true then...
        GenericEntityMapping<SampleEntity02>.Map(node, new SampleEntity02())
    }
}

在通用类型不需要硬编码的情况下，我该怎么办?

我的目标是这样的:
类型myType = pInfo.PropertyType.GetType();
GenericEntityMapping< myType> .Map(node，System.Activator.CreateInstance< myType>());

How can i do it where the type in the generic needs not to be hardcoded?

My goal is something like:
Type myType = pInfo.PropertyType.GetType();
GenericEntityMapping<myType>.Map(node, System.Activator.CreateInstance<myType>());

Is it possible?

推荐答案

MethodInfo method = typeof(GenericEntityMapping).GetMethod("Map");
MethodInfo generic = method.MakeGenericMethod(Type.GetType(pInfo.PropertyType.FullName));

object[] objParam = { node, System.Activator.CreateInstance(Type.GetType(pInfo.PropertyType.FullName)) };
pInfo.SetValue(entity, generic.Invoke(this, objParam), null);

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