将字符串转换为 int 时遇到问题

问题描述

在我的程序中，我有一个 treeView.在我正在处理的部分中，节点的 displayNames 是数字 integer 值，但显示为 strings.在我的程序中，我需要将这些 displayNames 转换并临时存储在一个 integer 变量中.我通常使用 Regex.Match() 来做到这一点，没有问题，但在这种情况下，我收到编译器错误:不能隐式将类型 'string' 转换为 'int'.

In my program I have a treeView. In the section that I am working with, the node's displayNames are numerical integer values, but are displayed as strings. I have come to a point in my program where I need to convert and temporarily store these displayNames in an integer variable. I usually use Regex.Match() to do this with no problem, but in this scenario I am getting the compiler error: Cannot implicitly convert type 'string' to 'int'.

这是我的代码:

//This is the parent node as you may be able to see below
//The children of this node have DisplayNames that are integers
var node = Data.GetAllChildren(x => x.Children).Distinct().ToList().First(x => x.identify == 'B');

//Get # of children -- if children exist
if (node.Children.Count() > 0)
{
     for (int i = 0; i < node.Children.Count(); i++)
     {
          //Error on this line!!**
          IntValue = Regex.Match(node.Children.ElementAt(i).DisplayName.Value, @"\d+").Value;
     }
}

*注意:DisplayName.Value 是一个 string

推荐答案

从string到int，使用int.Parse(string)，它返回传入的string所代表的int，如果输入格式不正确则抛出.

To get from string to int, use int.Parse(string), it returns the int represented by the passed string and throws if the input format is incorrect.

int.Parse(node.Children.ElementAt(i).DisplayName.Value)

如果您不想抛出，也可以使用 int.TryParse.在这种情况下，您将使用:

You can also use int.TryParse if you don't want the throw. in that case you would use:

int parsedValue;
if (int.TryParse(node.Children.ElementAt(i).DisplayName.Value, out parsedValue))
{
  ///Do whatever with the int
}

这篇关于将字符串转换为 int 时遇到问题的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！