问题描述
如何将两个32位的int数除以(int / int)返回给我 0
,但如果我使用 Decimal.Divide()
我得到了正确的答案?我绝不是ac#guy。
How come dividing two 32 bit int numbers as ( int / int ) returns to me 0
, but if I use Decimal.Divide()
I get the correct answer? I'm by no means a c# guy.
推荐答案
int
是整数类型;除以两个整数执行整数除法,即小数部分被截断,因为它不能存储在结果类型中(同样 int
!) 。相比之下,十进制
有一个小部分。通过调用 Decimal.Divide
,您的 int
参数将隐式转换为 Decimal
s。
int
is an integer type; dividing two ints performs an integer division, i.e. the fractional part is truncated since it can't be stored in the result type (also int
!). Decimal
, by contrast, has got a fractional part. By invoking Decimal.Divide
, your int
arguments get implicitly converted to Decimal
s.
您可以通过显式地强制转换其中一个来强制对 int
参数进行非整数除法浮点类型的参数,例如:
You can enforce non-integer division on int
arguments by explicitly casting at least one of the arguments to a floating-point type, e.g.:
int a = 42;
int b = 23;
double result = (double)a / b;
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