Python:计算字符串中列表项的出现次数

问题描述

如果我有以下列表

vowels = ["a","e","i","o","u"]

和另一个列表

words = ["happiness", "yellow"]

如何计算每个单词中的元音数量，即幸福= 3，黄色= 2?

how do I count the number of vowels in each word, i.e. happiness = 3, yellow=2?

推荐答案

使用列表理解:

>>> vowels = ["a","e","i","o","u"]
>>> words = ["happiness", "yellow"]
>>> [sum(c in vowels for c in word) for word in words]
[3, 2]

如果要在单词和出现之间进行映射，请使用字典理解:

If you want mapping between the words and occurences, use dictionary comprehension:

>>> {word: sum(c in vowels for c in word) for word in words}
{'happiness': 3, 'yellow': 2}

将vowels转换为set将使其更有效.

Converting vowels to set will make it more effective.

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