问题描述
我一定遗漏了一些非常简单的东西，因为这似乎不应该那么难.
I must be missing something really simple because this doesnt seem like it should be this hard.
这段代码是正确的:
clear all
whatever = @(x) deal(max(x), size(x));
input = randn(1,1000);
[a b] = whatever(input)
然而，我真正想做的是这样的:
However, what I really want to do is something like this:
clear all
whatever = @(x) deal(q = 3; q*max(x), size(x));
input = randn(1,1000);
[a b] = whatever(input)
为什么会中断?我不能在函数内部定义 q ?我想使用匿名函数的全部原因是，我实际上可以在其中执行多行代码，然后返回答案.我想匿名函数的最后一条语句是返回的内容，但是如何在其中定义变量?我不想在定义匿名函数之前定义 q.
Why does this break? I cant define q inside the function?? The whole reason I want to use anonymous functions is so that I can actually do multiple lines of code within them, and then return an answer. I suppose the last statement of an anonymous function is what is returned, but how do I define variables within them? I dont want to define q before the definition of the anonymous function.
谢谢.
推荐答案
不能在匿名函数中声明变量，因为它必须由表达式构造，ie:handle = @(arglist)expr
You cannot declare variables inside an anonymous function, because it must be constructed from an expression, i.e.: handle = @(arglist)expr
如果你想要可读性，在函数外定义q，像这样:
If you want readability, define q outside the function, like this:
q = 3;
whatever = @(x) deal(q * max(x), size(x));
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