本文介绍了如何释放仅包含指针的结构的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个在下面看到的结构:
I have a struct which you see below:
typedef struct _List {
Person *person; // pointer for people list
DoList *do; // Kinda timer, for checking list in some intervals
} List;
是否需要释放此结构?如果是这样,我该如何释放它?
Are there any need to free this struct? If so, how can i free it?
推荐答案
如果动态分配结构,则必须释放该结构.如果您动态分配成员并且在其他任何地方都没有对它们的引用,则必须在释放结构之前释放其成员.
You have to free the struct if you allocated it dynamically. You have to free its members before deallocating the struct if you allocated the members dynamically and don't have a reference to them anywhere else.
以下是一些示例:
void freeNotRequiredHere() {
List nonDynamicList;
Person nonDynamicPerson;
DoList nonDynamicDoList;
nonDynamicList.person = &nonDynamicPerson;
nonDynamicList.do = &nonDynamicDoList;
}
void freeRequiredForStructListOnly() {
List *dynamicList;
Person nonDynamicPerson;
DoList nonDynamicDoList;
dynamicList = (List *) malloc( sizeof(struct List) );
dynamicList->person = &nonDynamicPerson;
dynamicList->do = &nonDynamicDoList;
free( dynamicList );
}
void freeRequiredForStructListAndPersonOnly() {
List *dynamicList;
Person *dynamicPerson;
DoList nonDynamicDoList;
dynamicList = (List *) malloc( sizeof(struct List) );
dynamicPerson = (Person *) malloc( sizeof(Person) );
dynamicList->person = dynamicPerson;
dynamicList->do = &nonDynamicDoList;
free( dynamicPerson );
free( dynamicList );
}
void freeRequiredForStructListAndPersonOnly( DoList *notSureDoList ) {
List *dynamicList;
Person *dynamicPerson;
dynamicList = (List *) malloc( sizeof(struct List) );
dynamicPerson = (Person *) malloc( sizeof(Person) );
dynamicList->person = dynamicPerson;
dynamicList->do = notSureDoList;
// maybe notSureDoList was allocated with malloc(),
// maybe it is a non-dynamic stack variable.
// the calling function should deal with free()'ing notSureDoList
free( dynamicPerson );
free( dynamicList );
}
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