如何返回数组的特定元素?

问题描述

我想返回数组的奇数，但 Eclipse 似乎不接受我的返回 array[i]; 代码.我认为它需要返回整个数组，因为我将数组设置为我的方法的参数.正如我之前所说，我需要传递一个数组并获取该数组的特定元素作为回报.即使我将该数组设为静态，我如何返回单个元素?

I want to return odd numbers of an array yet Eclipse doesn't seem to accept my return array[i]; code. I think it requires returning a whole array since I set an array as a parameter to my method.As I said before, I need to pass an array and get a specific element of that array in return. Even if I make that array static, how do I return a single element?

好的，这里是:

public class newClass{
public static void main(String[] args)
{
    int [] newArray= new int [4];
    int [] array = {4,5,6,7};

    newArray[0] = array[0]+array[1]+array[2]+array[3];
    newArray[1] = array[0]*array[1]*array[2]*array[3];
    newArray[2] = findOut(array);

}

public static int findOut (int [] array3)
{
    int e1=0;
    int e2=0;
    for (int i=0; i<array3.length; i++)
    {
        if (array3[i]%2==0)
        {
            e1+=array3[i];
            array3[i]=e1
            return array3[i];
        }

        else
        {
            e2+=array3[i];
            array3[i]=e2;
            return array3[i];

        }

    }

}


}

我知道这里可能有很多错误，但我正在努力解决这个问题，我不仅返回奇数，我还将它们加在一起.

I know there are probably more than a few mistakes here but I'm working on it and I'm not only returning odd numbers, I also add them together.

推荐答案

你的代码应该是这样的:

You code should look like this:

public int getElement(int[] arrayOfInts, int index) {
    return arrayOfInts[index];
}

这里的要点是方法返回类型，它应该与数组元素类型匹配，如果你正在使用 main() - 这个方法也必须是静态的.

Main points here are method return type, it should match with array elements type and if you are working from main() - this method must be static also.

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