问题描述
我在多个文件夹中有多个源文件.有没有一种方法可以一次性编译所有文件而无需命名?
I have a number of source files in a number of folders.. Is there a way to just compile all of them in one go without having to name them?
我知道我可以说
g++ -o out *.cpp
但是当我尝试时
g++ -o out *.cpp folder/*.cpp
我收到一个错误.
这样做的正确方法是什么?我知道使用 makefile 是可能的，但可以直接使用 g++ 来完成吗?
What's the correct way to do this? I know it's possible with makefiles, but can it be done with just straight g++?
推荐答案
通过指定 folder/*.cpp，您是在告诉 g++ 编译 folder 中的 cpp 文件.没错.
By specifying folder/*.cpp you are telling g++ to compile cpp files in folder. That is correct.
您可能缺少的是告诉 g++ 在哪里可以找到那些 cpp 文件 #include 的附加文件.
What you may be missing is telling the g++ where to locate additional files that those cpp files #include.
为此，请告诉您的编译器也使用 -I include 该目录，如下所示:
To do this, tell your compiler to also include that directory with -I like this:
g++ -o out -I ./folder *.cpp folder/*.cpp
在某些情况下，我让编译器忘记了根/当前目录中的内容，因此我使用另一个 -I 手动将其指定到当前目录 .
In some circumstances I have had the compiler forget what was in the root/current directory, so I manually specified it with another -I to the current directory .
g++ -o out -I . -I ./folder *.cpp folder/*.cpp
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