问题描述
所以我有一个解决线性方程组的程序，但这不相关。那么我的程序会以下列形式传递两个线性方程：y = mx + b。我不知道如何使用Graphics2D绘制图形，我在解决它时遇到了一些麻烦。现在我不知道所以我没有可以告诉你的代码，但我可以告诉你：
So I have a program that solves a system of linear equations, but that is not relevant. So what happens is that my program pass two linear equations in the form of: y = mx +b. I do not know how I would graph this using Graphics2D, I am having some trouble figuring it out. Right now I have no idea so I have no code that I could show you, but I can tell you that:
- 我的程序正确将Ax + By = C转换为y = mx + B
- 在某些代码中使用drawLine（）方法显示示例会很有帮助
推荐答案
在代码中绘制一条线时，需要从点 A 指向 B 。 （一行段）
When you draw a line in code, you need to draw from point A to point B. (a line segment)
选择一个点 A 来启动该行，然后从 A 抽取到（AX + dx，AY + m * dx），其中 dx 是所需的行宽。
Pick a point A to start the line from, then draw from A to (A.X + dx, A.Y + m * dx), where dx is the desired width of the line.
例如，您可能需要 A 是你所在地区的一角， dx 是该地区的宽度。
For example, you may want A to be one corner of your area, and dx to be the width of the area.
这篇关于如何在java中使用y = mx + b绘制一条线？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！