本文介绍了帆布的OnDraw方法的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我以画线迷宫使用一对布尔数组的(水平和垂直)目前正在创建一个迷宫。

I am currently creating a maze using a pair of boolean array (horizontal and vertical) in order to draw lines for the maze.

迷宫每天只有5显示从一次阵列的bool。然后,我有谁是始终围绕一个用户,并为他的动作穿过迷宫下一组的bool的绘制。这是工作,因为它应该。

The maze only every displays 5 bools from the array at one time. Then, I have an user who is always centered and as he moves through the maze the next set of bools are drawn. This is working as it should.

这是我遇到的问题是:当用户移动到迷宫的某一部分的for循环绘制线条变得比布尔数组较高,因此崩溃的应用程序。请在下面找到一些code片段。

The issue that I am having is: when the user moves to a certain part of the maze the for loop drawing the lines becomes higher than the bool array and therefore crashes the app. Please find below some code snippets.

本的onDraw:

protected void onDraw(Canvas canvas) {
    canvas.drawRect(0, 0, width, height, background);
    int currentX = maze.getCurrentX(),currentY = maze.getCurrentY();
    int drawSizeX = 6 + currentX;
    int drawSizeY = 6 + currentY;
    currentX = currentX - 2;
    currentY = currentY - 2;

    for(int i = 0; i < drawSizeX - 1; i++)  {
        for(int j = 0; j < drawSizeY - 1; j++)  {
            float x = j * totalCellWidth;
            float y = i * totalCellHeight;
            if(vLines[i + currentY][j + currentX])  {
                canvas.drawLine(x + cellWidth,   //start X
                                y,               //start Y
                                x + cellWidth,   //stop X
                                y + cellHeight,  //stop Y
                                line);
            }
            if(hLines[i + currentY][j + currentX]) {
                canvas.drawLine(x,               //startX
                                y + cellHeight,  //startY
                                x + cellWidth,   //stopX
                                y + cellHeight,  //stopY
                                line);
            }
        }
        //draw the user ball
        canvas.drawCircle((2 * totalCellWidth)+(cellWidth/2),   //x of center
                          (2 * totalCellHeight)+(cellWidth/2),  //y of center
                          (cellWidth*0.45f),                    //radius
                          ball);
    }

编辑1 - 举 -

EDIT 1 - The Move -

public boolean move(int direction) {
    boolean moved = false;
    if(direction == UP) {
        if(currentY != 0 && !horizontalLines[currentY-1][currentX]) {
            currentY--;
            moved = true;
        }
    }
    if(direction == DOWN) {
        if(currentY != sizeY-1 && !horizontalLines[currentY][currentX]) {
            currentY++;
            moved = true;
        }
    }
    if(direction == RIGHT) {
        if(currentX != sizeX-1 && !verticalLines[currentY][currentX]) {
            currentX++;
            moved = true;
        }
    }
    if(direction == LEFT) {
        if(currentX != 0 && !verticalLines[currentY][currentX-1]) {
            currentX--;
            moved = true;
        }
    }
    if(moved) {
        if(currentX == finalX && currentY == finalY) {
            gameComplete = true;
        }
    }
    return moved;
}

如果有其他任何我需要澄清,请让我知道。

If there is anything else that I need to clarify please let me know.

先谢谢了。

推荐答案

drawSizeX / Y阵列上索引时currentX / Y足够高(长-6)

drawSizeX/Y indexes over the array when currentX/Y is high enough (length-6)

所以限制值Math.min(电流+ 6,array.length)

So limit the values to Math.min(current + 6, array.length)

这篇关于帆布的OnDraw方法的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

07-31 15:44