问题描述
我有一个用QPixmap填充的Qlabel,单击此标签后,我想启动一个进程/功能。我对QLabel类进行了如下扩展:
I have a Qlabel filled with QPixmap and I want to start a process/function once this label clicked. I had extended QLabel class as follows:
from PyQt5.QtCore import *
from PyQt5.QtWidgets import *
from PyQt5.QtGui import *
class QLabel_alterada(QLabel):
clicked=pyqtSignal()
def __init(self, parent):
QLabel.__init__(self, QMouseEvent)
def mousePressEvent(self, ev):
self.clicked.emit()
然后,在基于pyuic5的.py文件(我使用QtDesigner进行布局)中,将模块导入到我保存扩展的QLabel类的模块中,并在自动生成的setupui函数内部更改了我的标签
Then, in my pyuic5-based .py file (I used QtDesigner to do the layout) after importing the module where I save the extended QLabel class,inside the automatically generated setupui, function I changed my Label from
self.label1=QtWidgets.QLabel(self.centralwidget)
到
self.label1 = QLABEL2.QLabel_alterada(self.centralwidget)
最后,在核心应用python文件中,我将所有程序/我添加的应用程序功能所需要的所有类
Finally, in the core app python file where I put all the procedures/classes whetever needed to the application functionality I added
self.ui.label1.clicked.connect(self.dosomestuff)
应用程序不会崩溃,但标签仍然不可单击。有人可以帮我这个忙吗?
The application does not crashes but the labels still not clickable. Can someone give me some help on this?
预先感谢
推荐答案
我不明白为什么要将QMouseEvent传递给父构造函数,必须按如下所示传递parent属性:
I do not understand why you pass QMouseEvent to the parent constructor, you must pass the parent attribute as shown below:
class QLabel_alterada(QLabel):
clicked=pyqtSignal()
def __init__(self, parent=None):
QLabel.__init__(self, parent)
def mousePressEvent(self, ev):
self.clicked.emit()
为避免出现问题导入后,我们可以直接促销小部件,如下所示:
To avoid having problems with imports we can directly promote the widget as shown below:
我们放置 QLabel
并右键单击并选择升级到...
:
We place a QLabel
and right click and choose Promote to ...
:
我们得到以下对话框,并将 QLABEL2.h
放在头文件和 QL中升级类名称中的abel_changed
,然后按添加并升级
We get the following dialog and place the QLABEL2.h
in header file and QLabel_changed
in Promoted class Name, then press Add and Promote
然后我们在pyuic的帮助下生成.ui文件。获得以下结构:
Then we generate the .ui file with the help of pyuic. Obtaining the following structure:
├── main.py
├── QLABEL2.py
└── Ui_main.ui
获得以下结构:
class MainWindow(QtWidgets.QMainWindow):
def __init__(self, parent=None):
QtWidgets.QMainWindow.__init__(self, parent)
self.ui = Ui_MainWindow()
self.ui.setupUi(self)
self.ui.label.clicked.connect(self.dosomestuff)
def dosomestuff(self):
print("click")
if __name__ == "__main__":
import sys
app = QtWidgets.QApplication(sys.argv)
w = MainWindow()
w.show()
sys.exit(app.exec_())
这篇关于使用PyQt5使QLabel可点击的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!