使用python向RESTful API发出请求

问题描述

我有一个RESTful API，我已经在EC2实例上使用Elasticsearch的一个实现来暴露了索引一个内容的语料库。我可以通过从我的终端（MacOSX）运行以下内容来查询搜索：

I have a RESTful API that I have exposed using an implementation of Elasticsearch on an EC2 instance to index a corpus of content. I can can query the search by running the following from my terminal (MacOSX):

curl -XGET 'http://ES_search_demo.com/document/record/_search?pretty=true' -d '{
  "query": {
    "bool": {
      "must": [
        {
          "text": {
            "record.document": "SOME_JOURNAL"
          }
        },
        {
          "text": {
            "record.articleTitle": "farmers"
          }
        }
      ],
      "must_not": [],
      "should": []
    }
  },
  "from": 0,
  "size": 50,
  "sort": [],
  "facets": {}
}'

如何使用 python将其转换为API请求/ request 或 python / urllib2 （不知道要去哪一个 - 一直在使用urllib2，但听到请求更好...）我是否以标题或其他方式传递？

How do I turn above into a API request using python/requests or python/urllib2 (not sure which one to go for - have been using urllib2, but hear requests is better...)? Do I pass as a header or otherwise?

推荐答案

使用：

import requests
url = 'http://ES_search_demo.com/document/record/_search?pretty=true'
data = '''{
  "query": {
    "bool": {
      "must": [
        {
          "text": {
            "record.document": "SOME_JOURNAL"
          }
        },
        {
          "text": {
            "record.articleTitle": "farmers"
          }
        }
      ],
      "must_not": [],
      "should": []
    }
  },
  "from": 0,
  "size": 50,
  "sort": [],
  "facets": {}
}'''
response = requests.post(url, data=data)

根据您的API返回的响应类型，您可能需要查看 respo nse.text 或 response.json（）（或可能检查 response.status_code ）。请参阅快速入门文档，特别是。

Depending on what kind of response your API returns, you will then probably want to look at response.text or response.json() (or possibly inspect response.status_code first). See the quickstart docs here, especially this section.

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