使用字符串输入切换语句

问题描述

char type;
printf("What type of sort would you like to perform?\n");
scanf("%s", &type);
switch(type)
{
case 'bubble':
    bubble_sort();
case 'selection':
case 'insertion':
default:
    printf("invalid input\n");
}

我正在尝试创建一个程序，该程序根据用户的输入使用气泡，选择或插入排序对列表进行排序.

I am trying to create a program which sorts a list with either bubble, selection, or insertion sort based on the user's input.

我必须使用开关盒.

我在switch语句之前定义了一个变量"type"，然后使用scanf函数将其分配为"bubble"，"selection"或"insertion".

I have defined a variable "type" before the switch statement, and then use the scanf function to assign it either "bubble", "selection", or "insertion".

但是，当我运行代码并键入"bubble"时，它不执行我的bubble_sort函数(此处未显示)，而是采用默认情况.

However, when I run the code and type in "bubble", it does not carry out my bubble_sort function (not shown here) and instead resorts to the default case.

如何解决此问题?

对于'char'是定义我的"type"变量的正确方法还是switch语句是否只能用于单个字符，我有点不确定.

I am slightly uncertain as to whether 'char' was the correct way to define my "type" variable, or whether switch statements can only be used with single characters.

此外，如果我的代码格式不正确，对于我是该网站的新手，我深表歉意.

Also, I apologise if my code is not formatted correctly, as I am new to this site.

让我知道是否需要向该问题添加更多信息！

Let me know if I need to add any more information to this question!

推荐答案

由于类型是字符，并且开关可以使用单个字符，因此可以使用％c而不是％s扫描一个字符

Since type is a char and the switch can use single characters, you could scan for one character using %c instead of %s

char type;
printf ( "What type of sort would you like to perform?\n");
printf ( "Enter b for bubble\n");
printf ( "Enter s for selection\n");
printf ( "Enter i for insertion\n");
scanf ( " %c", &type);
switch ( type)
{
    case 'b':
        bubble_sort();
        break;
    case 's':
        selection_sort();
        break;
    case 'i':
        insertion_sort();
        break;
    default:
        printf("invalid input\n");
}

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