问题描述
在我的 java 项目中,我有几个类/java 文件,但是在 Menu 类中,该类存储了所有使用的东西列表.在数据方面,我存储了 6 个列表(2 个 ArrayLists 和 4 个 HashMaps),其中 1 个在 Menu 类中定义,其他在不同的类中.所以我需要在关闭程序时创建一个 savestate 和一个 loadstate 来恢复以前的状态.所有列表都使用 Serializable
in my java Project I have several classes/java files but is in Menu class that is stored all the lists of stuff that is used. In terms of data I store 6 Lists(2 ArrayLists and 4 HashMaps) which 1 is defined in Menu class and others are in different classes.So I need to create a savestate and a loadstate to when I close the program to restore the previous state. All the Lists are implemented with Serializable
是否可以保存所有菜单的状态并重新加载它,或者我必须单独保存所有列表?将所有内容保存在一个文件中会很棒.
Is it possible to save all the Menu's state and reload it or I've to save all the lists individually? Save all in one file would be great.
这是我拥有的函数,可以工作(没有警告/错误)并编译但不创建文件datafiles".
Here is the function I have, works(no warnings/errors) and compiles but doesn't creates the file "datafiles".
有什么想法吗?
private void MenuSave(){
String wd = System.getProperty("user.dir");
JFileChooser fc = new JFileChooser(wd);
int rc = fc.showDialog(null, "Select Data File Location to Save");
if (rc == JFileChooser.APPROVE_OPTION)
{
File file = fc.getSelectedFile();
String filename = file.getAbsolutePath();
savestate(lf, lc, lv, lcl,filename);}
}
public void savestate(Cars la, Bikes l2, Motos l3, Planes l4, People n1, Food n2, String filename){
int i;
File out = new File(filename);
ObjectOutputStream output = null;
try{
output = new ObjectOutputStream(new FileOutputStream(filename));
for(Car c : la.getCars().values()){
output.writeObject(c);
}
for(Bike b : l2.getBikes().values()){
output.writeObject(b);
}
for(Moto m : l3.getMotos().values()){
output.writeObject(m);
}
for(i=0;i<n1.size();i++)
{output.writeObject(n1.get(i)));
}
for(i=0;i<n2.size();i++)
{output.writeObject(n2.get(i)));
}
}catch (FileNotFoundException ex) {
ex.printStackTrace();
} catch (IOException ex) {
ex.printStackTrace();
} finally {
try {
if (output != null) {
output.flush();
output.close();
}
} catch (IOException ex) {
ex.printStackTrace();
}
}
}
推荐答案
所以我认为我只需要单独保存列表而不需要 for .1-选择保存文件的位置,然后将类保存在那里.2-读取只是解析输入并存储替换当前类....
So as I thought I just need to save the lists individually without that for .1-Choose where to save the file, then save the Classes in there.2-To read just parse the input and store replacing the current Classes....
String wd = System.getProperty("user.dir");
this.setAlwaysOnTop(false);
JFileChooser fc = new JFileChooser(wd);
fc.setDialogType((int)JFileChooser.SAVE_DIALOG);
int rc = fc.showDialog(null, "Select Data File");
this.setAlwaysOnTop(true);
if (rc == JFileChooser.APPROVE_OPTION)
{
File file = fc.getSelectedFile();
ObjectOutputStream output = null;
try{
output = new ObjectOutputStream(new FileOutputStream(file));
output.writeObject(list1);
output.writeObject(list2);
output.writeObject(list3);
....
output.close();
}catch (IOException x){
....
}catch(NullPointerException n){
....
}}
阅读是一样的:
String wd = System.getProperty("user.dir");
this.setAlwaysOnTop(false);
JFileChooser fc = new JFileChooser(wd);
fc.setDialogType((int)JFileChooser.OPEN_DIALOG);
int rc = fc.showDialog(null, "Select Data File to Load");
this.setAlwaysOnTop(true);
if (rc == JFileChooser.APPROVE_OPTION)
{
File file = fc.getSelectedFile();
String filename = file.getAbsolutePath();
ObjectInputStream input = null;
try{
input = new ObjectInputStream(new FileInputStream(file));
this.list1=(ListType1)input.readObject();
this.list2=(ListType2input.readObject();
....
}catch (IOException x){
...
}catch(ClassNotFoundException x){
...
}
}
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